Why Does My Capacitance Power Calculation Not Match the Given Answer?

AI Thread Summary
The discussion centers on a homework problem involving a capacitor with a voltage function of v(t) = 100*cos(2pi60t) and a capacitance of 0.01 Farads. The user successfully calculated the current i(t) as -120*pi*sin(2pi60t) Amperes but found that multiplying this current by the voltage does not yield the expected power result of -18,850sin(2pi120t) Watts. A suggestion is made to apply a trigonometric identity for Sin(2X) to resolve the discrepancy. The conversation highlights the importance of understanding the relationships between current, voltage, and power in capacitive circuits. Clarifying these calculations can help ensure accurate results in similar problems.
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Homework Statement



The voltage across a capacitor with a value of 0.01 Farads is v(t) 100*cos(2pi60t). Find i(t),p(t),and w(t).


Homework Equations



i(t)=Cv'(t) [current]
p(t)=i(t)v(t) [power]
w= integral of p(t) [Energy stored over time]

The Attempt at a Solution



I was able to correctly determine the current of capacitance, -120*pi*sin(2pi60t) Amperes. However, this multiplied by the voltage, does NOT equal the given answer of -18,850sin(2pi120t) Watts.

Could someone please clear this up for me? I would've used proper symbols, but the test is quite shortly, no time to mess with that ... :/

Thanks!
 
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Try using a trig identity for Sin(2X).
 
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