Why Does the Official Key State X=2.05 Instead of X=1 in This Adiabatic Process?

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SUMMARY

The forum discussion centers on the discrepancy between the official answer of X=2.05 and the participant's calculation of X=1 in an adiabatic process problem from JEE Advanced 2020. Key points include the importance of using the correct formula for work done, specifically W=p0v0[(1-x)3-3γ-1)/(1-γ)], and the necessity of including higher-order terms in the Taylor series expansion. Participants emphasize the need to correctly apply the adiabatic condition and the role of the parameter γ in their calculations.

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  • Understanding of adiabatic processes in thermodynamics
  • Familiarity with Taylor series expansions
  • Knowledge of the JEE Advanced exam format and typical problem types
  • Proficiency in using pressure-volume relationships in thermodynamic systems
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  • Study the derivation of work done in adiabatic processes using the formula W=p0v0[(1-x)3-3γ-1)/(1-γ)]
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  • Review common mistakes in solving thermodynamic problems, particularly in the context of the JEE Advanced exam
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Students preparing for the JEE Advanced exam, educators teaching thermodynamics, and anyone interested in understanding the nuances of adiabatic processes and their mathematical representations.

  • #31
Sorry, you lost me on this. I think we're talking about different things. X can't be 1/a + 1.05 because 1/a has units of inverse meters?
 
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  • #32
The sum of the coefficients of the first and second term is 2.05, but yes we can't add the coefficients together, they don't have common factor.
 
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  • #33
bhupesh said:
why are we adding these terms when a is a infinitesimal quantity
We are expanding the exact expression for the work in a Taylor series to 2nd order terms in a/R. So the result is not exact; we are retaining only the first 3 terms of the expansion.
 
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