Why is z = rcos(θ) and not z = rsin(θ) in surface integrals?

Miike012
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Look in the paint doc. I was wondering why they said z = rcos(θ) and not z = rsin(θ) and x = rcos(θ)
 

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The set-up is symmetric between x and z, so does it matter which is equated with the cos and which with the sin?
 
haruspex said:
The set-up is symmetric between x and z, so does it matter which is equated with the cos and which with the sin?

Well when i used sine I came out with a different answer but ill try again.
 
haruspex said:
The set-up is symmetric between x and z, so does it matter which is equated with the cos and which with the sin?

You are right the answers are the same. thanks.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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