Why won't any electrons flow through the resistor R2?

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In the discussed circuit, electrons do not flow through resistor R2 due to the presence of a parallel wire that offers a lower resistance path. The mathematical explanation involves understanding that the total resistance in the circuit is determined by R1 and R3, effectively excluding R2 when calculating current flow. When additional resistance, R4, is introduced in parallel with R2, it allows for a comparative analysis of current distribution. As R4 approaches zero, the current will predominantly flow through R1 and R3 instead of R2. This illustrates the principle that current takes the path of least resistance in a circuit.
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So I was doing a circuit with some friends, and the circuit breaks down such that There is what looks like a parallel circuit, with one branch containing just the wire, and the other branch containing a resistor. The answer to the question shows that the electrons will not flow through this resistor(R2). Why is this the case? Is there literally no electrons going throug the resistor? How do they know not to take that path?

So the answer R = R1 + R3

Mathematically how do we know this is being discluded? Or are we just assuming nothing will go through the resitor R2?
 

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Try putting in a resistance on the other leg and calculating what current will go through each. Then see what happens when the extra resistance goes to zero.
 
haruspex said:
Try putting in a resistance on the other leg and calculating what current will go through each. Then see what happens when the extra resistance goes to zero.

So in the limiting case where R2 -> 0 you just end up with the other resistance?
 
Plutonium88 said:
So in the limiting case where R2 -> 0 you just end up with the other resistance?
According to the diagram, you already have a resistance R2. I'm adding a resistance R4 in parallel with it. Find an expression for the fraction of the current that would pass through that, then see what happens as R4 tends to zero.
 
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