Why You Can't Hear Doppler Effect in Car/Train Scenario

AI Thread Summary
The discussion centers on why the Doppler effect might not be heard when traveling in a car near a speeding train. One key point is that if both the car and train are moving at the same velocity, the Doppler effect would not be perceived. Another consideration is the hypothetical scenario of a supersonic train, which raises questions about the feasibility of such speeds and the structural integrity of the train. The conversation highlights the complexities of sound perception in relation to relative motion. Overall, the conditions of relative speed and the nature of sound waves play crucial roles in experiencing the Doppler effect.
crosbykins
Messages
50
Reaction score
0

Homework Statement



-You are traveling in a car near a speeding train. The train whistle blows but you fail to hear the doppler effect. What conditions might prevent you from hearing it?



Homework Equations





The Attempt at a Solution


-Ok, all I can come up with is that maybe the car and train are traveling at the same velocity, so there would be no doppler effect or maybe the train is traveling at a speed greater than mach 1. Are these correct reasons?? Please help, thanks in advance.
 
Physics news on Phys.org


Your first guess is correct. Your second guess is wrong but freaking awsome- a supersonic train. I'd like to see the wheel and rail design of such a thing. Would a steel wheel rolling along at 1000 miles per hour even be able to hold together?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Replies
4
Views
2K
Replies
4
Views
2K
Replies
1
Views
2K
Replies
6
Views
4K
Replies
1
Views
2K
Replies
2
Views
4K
Back
Top