Width measurements and conversions

AI Thread Summary
The gap between tiles is calculated to be 0.18 centimeters and approximately 0.071 inches. To determine how many algae-thicknesses fit in the gap, the thickness of an algae cell is converted to micrometers, resulting in 1800 micrometers for the gap. Dividing 1800 micrometers by the algae cell width of 9.45 micrometers gives a result of about 190.476, which rounds to 190 algae cells. The calculations for the gap dimensions and the algae thicknesses are confirmed to be correct.
Jdpaul88
Messages
8
Reaction score
0

Homework Statement


The tiles are 2 thumbnail-thicknesses apart. A thumbnail has a thickness of about 0.90 mm. An inch is exactly 2.54 centimeters. One algae cell is 9.45 micrometers across.

a. How wide is the gap between tiles in centimeters?
b. How wide is the gap in inches
c. How many algae-thicknesses is the gap between tiles


Homework Equations





The Attempt at a Solution



First off, I just want to know if I did a and b correctly. To set up a, I took 0.90 mm x 2 to get 1.8 mm per gap. I then converted 1.8 millimeters in order to get to centimeters. I came up with 0.18 centimeters. For b, I just divided 0.18cm/2.54cm to get the answer in inches. As for c, I suppose I will just convert, what do you think about a and b so far?
 
Physics news on Phys.org
Jdpaul88 said:

Homework Statement




a. How wide is the gap between tiles in centimeters?
b. How wide is the gap in inches
c. How many algae-thicknesses is the gap between tiles


Homework Equations





The Attempt at a Solution



First off, I just want to know if I did a and b correctly. To set up a, I took 0.90 mm x 2 to get 1.8 mm per gap. I then converted 1.8 millimeters in order to get to centimeters. I came up with 0.18 centimeters. For b, I just divided 0.18cm/2.54cm to get the answer in inches. As for c, I suppose I will just convert, what do you think about a and b so far?

A and B would be correct.

C is asking how many algae diameters across. That requires a unit-less ratio.
 
LowlyPion said:
A and B would be correct.

C is asking how many algae diameters across. That requires a unit-less ratio.

Couldn't I just convert 9.45 micrometers to centimeters and divide by 0.18 cm to get the thickness between the gaps in terms of algae thicknesses?
 
Jdpaul88 said:
Couldn't I just convert 9.45 micrometers to centimeters and divide by 0.18 cm to get the thickness between the gaps in terms of algae thicknesses?

The question asks for how many will fit across. You divide the algae width INTO the gap in the tile dimension. Of course you need to make sure your units are correct, so the gap distance should be in the same units as the algae width.
 
So I converted 0.18 centimeters to micrometers and got 1800 micrometers. So then, I just take 1800 micrometers divded by 9.45 micrometers to get how many will fit across? 1800/9.45. I came up with 190.476, but since I can only have two significant figures in my answer, it would be 190 algae cells. How does that sound?
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top