Window Comparator: Understanding the Output Behavior and Common Errors

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SUMMARY

The discussion centers on the functionality of a window comparator in operational amplifier circuits. Users express confusion regarding the output behavior when the input voltage is within the specified reference values. Specifically, with Vref(high) set at 5V, Vref(low) at 1V, and a 3V input, participants note discrepancies between expected and actual output voltages. The consensus suggests that the output should be high when the input is within the window, despite observations indicating otherwise, leading to speculation about potential errors in the referenced textbook.

PREREQUISITES
  • Understanding of operational amplifiers and their configurations
  • Familiarity with window comparator functionality
  • Basic knowledge of voltage reference values and input-output relationships
  • Experience with circuit simulation tools like LTSpice
NEXT STEPS
  • Research the operational amplifier configurations for window comparators
  • Learn to simulate circuits using LTSpice for practical verification
  • Explore common errors in electronics textbooks and how to identify them
  • Study the active low output behavior in comparator circuits
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Electronics students, hobbyists working with operational amplifiers, and educators seeking to clarify window comparator behavior in circuit design.

Alex Hughes
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So I've been reading an intro book to electronics and I got to a section about operational amplifiers. It talks about different uses of them and how they can be used as comparators. It then talks about a specific comparator called a window comparator which will output a positive voltage if the input voltage is in between the high and low reference values. Here is the diagram they give:

upload_2018-3-24_13-41-16.png


I understand the theory, but according to this diagram I don't seem to get the values they say I should get. For example, I put the Vref(high) at 5v and the low at 1V with a 3V input. According to the book I should get a positive voltage for Vout. However in the top comparator, The noninverting input (+ side) is at a lower value than the inverting input. According to the book, this means the output should be negative, right? In the bottom comparator, the noninverting input is also lower than the inverting input, once again resulting in a negative output. Since there are two diodes on both sides, this wouldn't allow any of the signal to get through and Vout would be 0. Can somebody explain to me why they say you should get a positive output if the input voltage lies between the two reference values then? Thanks.
 

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Alex Hughes said:
For example, I put the Vref(high) at 5v and the low at 1V with a 3V input.

Have you implemented this either on a breadboard (or something) or using electronics simulator software and in what way i.e. what components you are using and what are the voltages you apply (##V_{cc}, V_{REF}, V_{in}##)?
 
Is there a requirement what the logic output is? In other words is there a reason that the output needs to be high when the input is within the window? I can't see what your book says. Your circuit will output a high when outside the window and a low when within the window.
 
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They explicitly said in the book that if the input voltage lies within both reference values, the output will be positive. You can read it here. Figure 3-12 is the diagram I attached above.
upload_2018-3-24_17-41-45.png


I've caught errors in this book before, is this another one of those errors?
 

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Alex Hughes said:
They explicitly said in the book that if the input voltage lies within both reference values, the output will be positive. You can read it here. Figure 3-12 is the diagram I attached above.
View attachment 222679

I've caught errors in this book before, is this another one of those errors?
I would say.
 
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Alex Hughes said:
Can somebody explain to me why they say you should get a positive output if the input voltage lies between the two reference values then? Thanks.
Looks to me also that the output is active low...
Alex Hughes said:
I've caught errors in this book before, is this another one of those errors?
There's a free version of LTSpice that is especially helpful for students. I'd guess that if you simulated this circuit in LTSpice to confirm the hint from @Averagesupernova you would get extra credit... :smile:
 
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