Work and Energy Theorem and Kinetic Energy

AI Thread Summary
A space probe with a mass of 5.0x10^4 kg is initially traveling at 11,000 m/s, and retrorockets apply a force of 4.0x10^5 N over a distance of 2500 km to reduce its speed. The work done by the retrorockets is calculated to be 1x10^12 J. The work-energy theorem is applied, where the work done equals the change in kinetic energy, leading to the equation 1x10^12 J = 1/2(5x10^4 kg)(vf^2) - 3.025x10^12 J. The user struggles with the calculations, initially obtaining incorrect values for the final speed, vf, but later corrects a typo in the energy equation. The discussion emphasizes the importance of careful unit conversion and accurate arithmetic in solving physics problems.
rmarkatos
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A 5.0x10^4kg space probe is traveling at a speed of 11,000m/s through deep space. Retrorockets are fired along the line of motion to reduce the probe's speed. The retrorockets generate a force of 4.0x10^5N over a distance of 2500km. What is the final speed of the probe.

For this problem i know exactly what to do but i know i am getting the wrong answer because I have odd answer selections.

I used W=Fd=1/2m(vf^2)-1/2m(vi^2). I know this is correct because when i plug in the correct answer for vf=9,000 m/s it equals the other side of the equation so i know i am right but for some reason in the process of solving i am not sure what i am doing wrong because i keep getting the wrong answer for vf. It is kind of strange because my units in every part of solving the equation come out correctly.

Any suggestions?
 
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Are you manipulating the equality correctly? Perhaps if you were to show your steps we may be able to comment further.
 
Yes, sorry about that i should of.

First i converted km to meters because we work in the mks system

(4x10^5N)(2.5X10^6m)=w
=1x10^12J

1x10^12J=1/2(5x10^4kg)(vf^2)-1/2(5x10^4kg)(11,000m/s)^2

1x10^12J=1/2(5x10^4kg)(vf^2)-3.025J

from here i tried different ways to solve the equation but each way i still get the wrong answer. I added the 3.025J to both sides and then multiplied the 1/2(5x10^4). Then i divided the 4.025J by the 25,000kg and then solved for vf by taking the square root of both sides but for some reason my answer does not really come out relativlely close 9000m/s
 
rmarkatos said:
1x10^12J=1/2(5x10^4kg)(vf^2)-3.025J
Do you not think this number looks a little small?
 
Oh sorry a bit of typo there. It is supposed to be-3.025x10^12. Sorry i forgot to type that in there but when i was doing the problem i did have it correctly written.
 
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