A parallel-plate capacitor is charged to an electric potential of 100 V by moving 4x10^19 electrons from one plate to the other. How much work was done?
How much work was done?
The Attempt at a Solution
Work is then simply equals to -q*deltaV. Q= number of electrons times charge per electron.
W= +4E19 * 1.6E-19 * 100= 640 J
But the answer I was given was 320 J. I don't see a divisible of 2 anywhere that I can account for.
Please help. Thanks.