Work, Energy, Power Problems: No Mass? No Speed?

AI Thread Summary
The discussion focuses on calculating the efficiency of a skier descending a 65 m hill, achieving a speed of 23 m/s at the bottom. It clarifies that mass is not needed for the efficiency calculation because it cancels out in the equations for energy input and output. The energy input is calculated using gravitational potential energy (Eg = mgh), while the energy output is derived from kinetic energy (Ek = mv^2/2). The final efficiency is determined to be 41.5%. Additionally, the thread addresses the challenge of calculating power without time, suggesting that mass can be treated as an unknown in the equations.
harujina
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Homework Statement



Athletes who compete in downhill skiing try to lose as little energy as possible. A skier starts from rest at the top of a 65 m hill and skis to the bottom as fast as possible. When she arrives at the bottom, she has a speed of 23 m/s. Calculate the skier's efficiency. Explain why the mass of the skier is not required when calculating the efficiency.

Homework Equations



Eg = mgh

The Attempt at a Solution



I don't understand since Eg = mgh, and I'm only given height and velocity. How could I possibly find the skier's efficiency without mass?

*Also, another question asks how I could determine power without time. How is this possible when P = E/t?
 
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Just put the mass in as an unknown m and plod through the equations. See what happens.
For the other question, you need to post it in full.
 
Since mass is unknown so put mass as unknown, at the end the mass will cancel out because Eout/Ein*100%...
Follow the steps
E input = mgh
mass= unknown, so E input= mass*9.8ms^-2*65m = 637m
E input = 637*mass

E out = E kinetic at bottom of hill, so Ek= (mv^2)/2
E out= 264.5*mass
Finally, Efficiency= Eout/Ein *100%
Efficiency= (264.5*mass)/(637*mass) * 100%
Since the mass is same, so they cancel out: it will not effect the answer...
Efficiency = 41.5%
 
haruspex said:
Just put the mass in as an unknown m and plod through the equations. See what happens.
For the other question, you need to post it in full.
[/QUOT
harujina said:

Homework Statement



Athletes who compete in downhill skiing try to lose as little energy as possible. A skier starts from rest at the top of a 65 m hill and skis to the bottom as fast as possible. When she arrives at the bottom, she has a speed of 23 m/s. Calculate the skier's efficiency. Explain why the mass of the skier is not required when calculating the efficiency.

Homework Equations



Eg = mgh

The Attempt at a Solution



I don't understand since Eg = mgh, and I'm only given height and velocity. How could I possibly find the skier's efficiency without mass?

*Also, another question asks how I could determine power without time. How is this possible when P = E/t?
https://www.physicsforums.com/threa...problems-no-mass-no-speed.721041/post-6471736
 
smokiee said:
Since mass is unknown so put mass as unknown, at the end the mass will cancel out because Eout/Ein*100%...
Follow the steps
E input = mgh
mass= unknown, so E input= mass*9.8ms^-2*65m = 637m
E input = 637*mass

E out = E kinetic at bottom of hill, so Ek= (mv^2)/2
E out= 264.5*mass
Finally, Efficiency= Eout/Ein *100%
Efficiency= (264.5*mass)/(637*mass) * 100%
Since the mass is same, so they cancel out: it will not effect the answer...
Efficiency = 41.5%
The thread is over 7 years old.
 
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