Work, Energy, Power Problems: No Mass? No Speed?

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Homework Help Overview

The discussion revolves around a problem in the context of work, energy, and power, specifically focusing on a skier's efficiency as she descends a hill. The problem presents a scenario where the skier's mass is not provided, raising questions about how to calculate efficiency without this information.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the idea of treating mass as an unknown variable in the efficiency calculation, suggesting that it will cancel out in the final formula. There are questions about how to approach the calculation of power without a time variable, indicating uncertainty about the relationship between energy and power.

Discussion Status

Some participants have provided guidance on how to proceed with the calculations by incorporating mass as an unknown. There is an ongoing exploration of the implications of not having mass in the efficiency calculation and how it affects the outcome.

Contextual Notes

The original poster expresses confusion regarding the absence of mass in the efficiency calculation and questions how to determine power without time, highlighting potential constraints in the problem setup.

harujina
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Homework Statement



Athletes who compete in downhill skiing try to lose as little energy as possible. A skier starts from rest at the top of a 65 m hill and skis to the bottom as fast as possible. When she arrives at the bottom, she has a speed of 23 m/s. Calculate the skier's efficiency. Explain why the mass of the skier is not required when calculating the efficiency.

Homework Equations



Eg = mgh

The Attempt at a Solution



I don't understand since Eg = mgh, and I'm only given height and velocity. How could I possibly find the skier's efficiency without mass?

*Also, another question asks how I could determine power without time. How is this possible when P = E/t?
 
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Just put the mass in as an unknown m and plod through the equations. See what happens.
For the other question, you need to post it in full.
 
Since mass is unknown so put mass as unknown, at the end the mass will cancel out because Eout/Ein*100%...
Follow the steps
E input = mgh
mass= unknown, so E input= mass*9.8ms^-2*65m = 637m
E input = 637*mass

E out = E kinetic at bottom of hill, so Ek= (mv^2)/2
E out= 264.5*mass
Finally, Efficiency= Eout/Ein *100%
Efficiency= (264.5*mass)/(637*mass) * 100%
Since the mass is same, so they cancel out: it will not effect the answer...
Efficiency = 41.5%
 
haruspex said:
Just put the mass in as an unknown m and plod through the equations. See what happens.
For the other question, you need to post it in full.
[/QUOT
harujina said:

Homework Statement



Athletes who compete in downhill skiing try to lose as little energy as possible. A skier starts from rest at the top of a 65 m hill and skis to the bottom as fast as possible. When she arrives at the bottom, she has a speed of 23 m/s. Calculate the skier's efficiency. Explain why the mass of the skier is not required when calculating the efficiency.

Homework Equations



Eg = mgh

The Attempt at a Solution



I don't understand since Eg = mgh, and I'm only given height and velocity. How could I possibly find the skier's efficiency without mass?

*Also, another question asks how I could determine power without time. How is this possible when P = E/t?
https://www.physicsforums.com/threa...problems-no-mass-no-speed.721041/post-6471736
 
smokiee said:
Since mass is unknown so put mass as unknown, at the end the mass will cancel out because Eout/Ein*100%...
Follow the steps
E input = mgh
mass= unknown, so E input= mass*9.8ms^-2*65m = 637m
E input = 637*mass

E out = E kinetic at bottom of hill, so Ek= (mv^2)/2
E out= 264.5*mass
Finally, Efficiency= Eout/Ein *100%
Efficiency= (264.5*mass)/(637*mass) * 100%
Since the mass is same, so they cancel out: it will not effect the answer...
Efficiency = 41.5%
The thread is over 7 years old.
 

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