Would one weigh more on the equator or on the North Pole?

AI Thread Summary
Weight differs between the equator and the North Pole due to variations in gravitational acceleration, which is approximately 9.78 m/s² at the equator and 9.83 m/s² at the poles. The Earth's shape, being an oblate spheroid, means that polar points are closer to the core, contributing to increased weight at the North Pole. Additionally, the Earth's rotation creates a centrifugal force that reduces weight at the equator compared to the poles. Thus, one would weigh more at the North Pole than at the equator. Understanding these factors clarifies the reasoning behind weight differences based on geographic location.
einsteinette
Messages
12
Reaction score
0
Hello, just wondering if you could apply Fg=mg to this. So the gravitational forces on the equator versus on the North Pole would differ and therefore, you would weigh more on the North Pole. According to what I found, the the gravitational acceleration is 9.78 m/s2 at the equator and 9.83 m/s2 at the poles. Does this reasoning make sense?
 
Physics news on Phys.org
Sure;

Earth is not a perfect sphere as we all know, Polar points are closer to the core of the Earth than Equator.So you weigh more in the North pole then equator.

And of course you can use F=m.g to see that, just insert the "g" for poles and equator,
 
Thanks, good to know that I make sense.
 
Cryphonus said:
Earth is not a perfect sphere as we all know, Polar points are closer to the core of the Earth than Equator.So you weigh more in the North pole then equator.

Not only that, but the Earth is rotating as well, so there is a centrifugal force pulling you up that decreases with higher latitudes.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .

Similar threads

Replies
2
Views
1K
Replies
9
Views
2K
Replies
10
Views
3K
Replies
6
Views
1K
Replies
9
Views
4K
Replies
2
Views
15K
Replies
1
Views
7K
Replies
1
Views
11K
Back
Top