Would one weigh more on the equator or on the North Pole?

AI Thread Summary
Weight differs between the equator and the North Pole due to variations in gravitational acceleration, which is approximately 9.78 m/s² at the equator and 9.83 m/s² at the poles. The Earth's shape, being an oblate spheroid, means that polar points are closer to the core, contributing to increased weight at the North Pole. Additionally, the Earth's rotation creates a centrifugal force that reduces weight at the equator compared to the poles. Thus, one would weigh more at the North Pole than at the equator. Understanding these factors clarifies the reasoning behind weight differences based on geographic location.
einsteinette
Messages
12
Reaction score
0
Hello, just wondering if you could apply Fg=mg to this. So the gravitational forces on the equator versus on the North Pole would differ and therefore, you would weigh more on the North Pole. According to what I found, the the gravitational acceleration is 9.78 m/s2 at the equator and 9.83 m/s2 at the poles. Does this reasoning make sense?
 
Physics news on Phys.org
Sure;

Earth is not a perfect sphere as we all know, Polar points are closer to the core of the Earth than Equator.So you weigh more in the North pole then equator.

And of course you can use F=m.g to see that, just insert the "g" for poles and equator,
 
Thanks, good to know that I make sense.
 
Cryphonus said:
Earth is not a perfect sphere as we all know, Polar points are closer to the core of the Earth than Equator.So you weigh more in the North pole then equator.

Not only that, but the Earth is rotating as well, so there is a centrifugal force pulling you up that decreases with higher latitudes.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...

Similar threads

Replies
2
Views
1K
Replies
9
Views
2K
Replies
10
Views
3K
Replies
6
Views
1K
Replies
9
Views
4K
Replies
2
Views
15K
Replies
1
Views
7K
Replies
1
Views
11K
Back
Top