Year 12: Cambridge Physics Problem (Distance of O atom in atmosphere)

AI Thread Summary
At an altitude of 100 km, the atmospheric density is approximately 10^-14 kg/m^3 and the temperature is 2000K, with atomic oxygen as the primary component. The discussion revolves around estimating the atmospheric pressure at 1000 km, with participants questioning the linearity of pressure change with altitude and the applicability of the ideal gas law. It is suggested that the problem may contain a typo regarding the altitude of 1000 km, as calculations for pressure should be based on the conditions at 100 km. The kinetic theory of temperature is highlighted, noting that at low pressures, thermal equilibrium takes longer to achieve, affecting temperature readings. Participants emphasize using the ideal gas equation for accurate calculations rather than relying solely on root mean square speeds.
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At an altitude of about 100km above the Earth's surface, the density and temperature of the atmosphere are about 10^-14 kg/m^3 and 2000K, respectively. At this altitude, the major constituent of the atmosphere is atomic oxygen. Use this information to estimate the pressure of the atmosphere at an altitude of 1000km.

On average, how far apart are the oxygen atoms? What is their root mean square speed? Discuss whether the temperature of a gas at this pressure can be interpreted in the same way as the temperature of a gas at normal atmospheric pressure.

Attempt:

The first thing that crossed my mind is whether the pressure of the atmosphere oxygen changes linearly with the height of the atmosphere. But how do I know whether it's a linear variation or not?

What other factors should I consider when attempting the question? P=ρhg doesn't really help, I think.

Thank you!
 
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johnconnor said:
Attempt:

The first thing that crossed my mind is whether the pressure of the atmosphere oxygen changes linearly with the height of the atmosphere. But how do I know whether it's a linear variation or not?

I don't think it is linear. The pressure depends on the temperature, and density of oxygen molecules, and they are both not related linearly to the height from sea level. Aren't you given the temperature at 1000km height?
 
johnconnor said:
At an altitude of about 100km above the Earth's surface, the density and temperature of the atmosphere are about 10^-14 kg/m^3 and 2000K, respectively. At this altitude, the major constituent of the atmosphere is atomic oxygen. Use this information to estimate the pressure of the atmosphere at an altitude of 1000km.

On average, how far apart are the oxygen atoms? What is their root mean square speed? Discuss whether the temperature of a gas at this pressure can be interpreted in the same way as the temperature of a gas at normal atmospheric pressure.

Attempt:

The first thing that crossed my mind is whether the pressure of the atmosphere oxygen changes linearly with the height of the atmosphere. But how do I know whether it's a linear variation or not?

What other factors should I consider when attempting the question? P=ρhg doesn't really help, I think.

Thank you!

I think the 1000 km must be a typo. I think it was meant to read 100 km. The problem asks you to calculate the pressure at the altitude, which you can get from the ideal gas law. If you want to get the parameters at 1000 km, you need to know the temperature profile, and you also need to take into account the changes in g with radial distance. I don't think this is what was intended by the question.
 
Chestermiller said:
I think the 1000 km must be a typo. I think it was meant to read 100 km. The problem asks you to calculate the pressure at the altitude, which you can get from the ideal gas law. If you want to get the parameters at 1000 km, you need to know the temperature profile, and you also need to take into account the changes in g with radial distance. I don't think this is what was intended by the question.

You're right. The guide didn't mention anything about a variation with height at ten times the height too. Thanks. Will solve it now.

p = (density)(rms square speed)/3 = (density)(temperature)/3
(using the proportion that rms speed is proportional to temperature)
p = 6.67E-12

But the guide given squares the temperature, giving the pressure as 1.33E-8. Why so?
 
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efed2049 said:
Thank you for sharing!
http://www.digoko.info./kv.gif

You're welcome! I'd appreciate yr participating in the discussions to solve the questions as a sign of thanks!
 
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20120703_114400.jpg


As for the final part, the guide says
The kinetic theory concept of temperature is that it is measured by the average kinetic energy per atom. The same idea applies but where he pressure is very low, it takes a long time for thermal equilibrium to be established between the atmosphere and the thermometer used.

What other comments have you got? I can't think of any... :P
 
The kinetic theory concept of temperature is that it is measured by the average kinetic energy per atom. The same idea applies but where he pressure is very low, it takes a long time for thermal equilibrium to be established between the atmosphere and the thermometer used.

Isn't the given explanation clear? Since the pressure and molecule density is very low, there are lesser molecules that collide with the thermometer, and this makes attaining the same temperature as that of the atmosphere, take a lot of time. It implies you would need to keep the thermometer in there for a longer time than you normally keep in the 'near-earth' atmosphere to measure temperature.

As for your work, I think you should instead consider the ideal gas equation over the mean square speeds. <C> is proportional to T, but it is unknown what the proportionality constant is...Rearranging the ideal gas equation will give you,

PV = \frac{m}{M}RT \\ PM = \rho RT

Where M is the molecular mass of oxygen.
 
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