Where Does the Electric Field Cancel Between Two Unequal Charges?

AI Thread Summary
The discussion centers on determining where the electric field strength is zero between two isolated point charges, -7μC and +2μC. The consensus is that the cancellation point is located at a specific position, which is identified as point D. The negative charge has a greater magnitude, leading to a stronger pulling effect compared to the pushing effect of the positive charge. Participants emphasize understanding the physics behind electric fields and suggest visualizing the forces at play rather than relying solely on calculations. Ultimately, the discussion highlights the importance of conceptualizing electric fields to solve such problems effectively.
calculator20
Messages
47
Reaction score
0
Two isolated point charges -7μC and +2μC are at a fixed distance apart. At which point is is it possible for the electric field strength to be zero?

ImageUploadedByPhysics Forums1391411189.234661.jpg


I don't know where to start with only 2 numbers and no distances. I know that E= kQ/r^2
 
Physics news on Phys.org
Well ... if the two charges were equal, same charge, which point has zero field?
"Half way between them." right? You don't need distances to answer the question.

It kinda looks like they want you to pick point A or point D. That makes it easier.
One point is to the left and the there to the right - only one could plausibly have a zero field.
You get to do it either by understanding the physics or by doing the algebra with the distance being D.
 
Thanks for your help but I still don't understand. The answer is D but I can't see how you would know that with no numbers apart from the charges. I've tried calculating E using sample distances and get no where near zero. I want to understand the physics and the algebra but neither are making sense as yet.
 
calculator20 said:
. The answer is D but I can't see how you would know that with no numbers apart from the charges. I've tried calculating E using sample distances and get no where near zero. I want to understand the physics and the algebra but neither are making sense as yet.

Here's the idea:

Think about the negative charges as ''pullers'' and positive as ''pushers'' (owing to their electric field lines). Now, since -7μC has a greater magnitude, its pulling strength (or electric field strength) is higher than the pushing strength of 2μC, right?

So, to check the zero field intensity, position a charge in the points A and D and try to find out the position such that the pushing strength of 2μC just overcomes/balances the pulling strength of -7μC keeping in mind that the farther you go, lesser your field strength becomes.
 
Thank you, that's a really helpful way to picture it. I can see how it would be solved as a multiple choice question without calculations now. Thanks.
 
calculator20 said:
Two isolated point charges -7μC and +2μC are at a fixed distance apart. At which point is is it possible for the electric field strength to be zero?

View attachment 66245

I don't know where to start with only 2 numbers and no distances. I know that E= kQ/r^2
You can establish precisely where the field strength will be zero by expressing it in terms of the distance d between the charges (i.e., scaling to the distance between the charges).
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top