Recent content by xoxomae

Thank you. Do you by any chance know any way to solve that integral by hand? I solved it on mathematica and it gave me ##P=e^\frac{-{k_{0}}^{2}\hbar}{4mw}## but I have no idea how to solve it by hand. Thanks again.

Ah right. So would this be the probability of the system still being in the ground state? ##\left | \int_{-\infty}^{\infty} \psi_{0} \psi_{0} e^{ik_{o}x}dx\right |^2=P##

Homework Statement An interaction occurs so that an instantaneous force acts on a particle imparting a momentum ## p_{0} = \hbar k_{0}## to the ground state SHO wave function. Find the probability that the system is still in its ground state. Homework Equations ##\psi _{0} =\left(...

Sorry, I forgot to mention that f(r) = div (grad (1/r))

Why is it possible that ∫∫∫ V f(r) dV ≠ 0 even if f(r) =0

Is the position vector r=xi+yj+zk just r=rerin spherical coordinates?

Is v(r) ≡ v(x,y,z)

Homework Statement Find the Fourier spectrum of the following equation Homework Equations ##F(\omega)=\pi[\delta(\omega - \omega _0)+\delta(\omega +\omega_0)]## The Attempt at a Solution Would the Fourier spectrum just be two spikes at ##+\omega _0## and ##-\omega _0## which go up to infinity?

What would the angular velocity for a phasor be for a triangle wave? I think it would vary sinusoidally but I can't find an expression

Okay, so i drew a picture and realized that I made a mistake. I got to Change in x = l/2 * (1- cos(x))

Would I have to use cos (x) instead of sin (x)? Umm yes that's the question :)

I used a factor of sin (x) because the change in the y-axis * mg is equal to total potential energy y = r sin (theta) when changing between polar and cartesian coordinates Is this the wrong way to think about it?

Homework Statement Determine the maximum kinetic energy of a uniform rod of mass 0.5Kg and length 0.75 that has an angular displacement of 5 degrees. Homework Equations y = rsin (x) where x is the angular displacement The Attempt at a Solution Using conservation of energy ETotal = EMech +...

Thank You :)

Ah i think I understand Q = ((mC- 6mE) - (mB - 5mE + mE))c2 Q = (mC - mB - 2me) c2 Is this right?