How Is Electric Flux Calculated for a Charged Sphere?

AI Thread Summary
To calculate the electric flux for a uniformly charged conducting sphere with a diameter of 1.6 m and a surface charge density of 8.0 µC/m², the net charge can be determined using the formula q = surface charge density x area. The area of the sphere is calculated as A = 4π(0.8 m)², resulting in a charge of approximately 6.434e-11 C. The electric field (E) at the surface is found using E = k(q/r²), yielding a value of about 0.90377 N/C. The total electric flux can then be calculated using the formula flux = E x A, or alternatively, by applying Gauss's law, which simplifies the process. This discussion emphasizes the importance of understanding both direct calculations and the application of Gauss's law in electrostatics.
22steve
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Homework Statement



A uniformly charged conducting sphere of 1.6 m diameter has a surface charge density of 8.0 µC/m2. What is the net charge of the sphere, and what is the total electric flux leaving the surface of the sphere?

Homework Equations



surface charge density = q/A
flux = E x A
flux = charge enclosed/ permittivity constant (Epsilon-naught)

The Attempt at a Solution


q = surface charge density x A
so (8e-12)x(4xpix 0.8^2) = 6.434e-11
then E = k(q/r^2) = .90377 = E
so flux = E x A = .90377x 4x pi x .8^2
 
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22steve said:

The Attempt at a Solution


q = surface charge density x A
so (8e-12)x(4xpix 0.8^2) = 6.434e-11
Careful: μC = 10-6C.
then E = k(q/r^2) = .90377 = E
so flux = E x A = .90377x 4x pi x .8^2
That's too much work. Once you find the correct charge, just use Gauss's law to find the flux. (But your method would work also. :wink:)
 
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