Finding the total vertical distance - transverse wave

AI Thread Summary
The discussion revolves around calculating the total vertical distance a colored dot moves in a transverse wave over 3.00 seconds, given an amplitude of 5.89 cm and a frequency of 5.00 Hz. The initial attempt incorrectly calculated displacement instead of total distance, leading to confusion. The correct approach involves recognizing that the dot completes several oscillations, thus covering a total vertical distance rather than returning to the starting point. The key takeaway is that total distance is the amplitude multiplied by the number of oscillations within the given time frame. Understanding this distinction between displacement and distance is crucial for solving the problem accurately.
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Homework Statement



Suppose the amplitude and frequency of the transverse wave in the figure are, respectively, 5.89 cm and 5.00 Hz. Find the total vertical distance (in cm) through which the colored dot moves in 3.00 s.

http://i45.tinypic.com/3007ihy.png

Homework Equations



y = A sin (2pi x f x t - (2pi x)/λ)
v=λf
v= x/t

The Attempt at a Solution



x=vt
λ=v/f

x/λ = vt/ (v/f) = t x f = 15

Plug in x/λ = 15
Plug in A = .0589m
Plug in f = 5 Hz
Plug in t = 3.00 seconds

Answer = 0m

However, the online system says it is incorrect. I have no other strategy besides this one? Can someone help?
 
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You have found the displacement. Which is zero, because in 3.00 seconds the dot makes a few COMPLETE oscillations and returns where it was. You need to find the distance, which is the length of the total path the dot has gone through.
 
OH
y = displacement and not distance! Got it.

Thanks so much!
 
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