Lift relative velocity problem.

AI Thread Summary
The discussion revolves around a lift system where a motor unwinds a cable affecting the lift's velocity. For part a, it is established that the velocity of point P is -3 times the velocity of point A. In part b, confusion arises regarding the relationship between the unwinding speed of the cable and the lift's velocity. It is clarified that while the motor unwinds the cable at 2 m/s, the lift's velocity is only 0.5 m/s due to the mechanics of the system. The key takeaway is that the lift's velocity is a quarter of the cable's unwinding speed, highlighting the importance of understanding the system's dynamics.
Legendon
Messages
21
Reaction score
0

Homework Statement


motor is mounted on top of lift.
a)if p moves by y, what is the displacement of Pt A? Prove that Vp=-3Va.
b)If motor unwidns cable at const rate 2m/s, what is vel of cable wrt lift.
Prove vel of lift is 0.5m/s


Homework Equations





The Attempt at a Solution


I can do part a. I have prob with part b. If motor releases cable at 2m/s, can i take it that pt p moves 2m/s. so Va is 2/-3=-0.667. Since pt a is connected to the lift, the vel of cable wrt lift is 2+0.667=2.667.
But velocity of lift is 0.5 so the vel of cable wrt to lift is 2.5. This is getting confusing.
 

Attachments

  • Untitled-1.jpg
    Untitled-1.jpg
    11.2 KB · Views: 479
Physics news on Phys.org
anyone ?
 
this is a better picture
 

Attachments

  • cmd.jpg
    cmd.jpg
    15.7 KB · Views: 472
Conservation of energy is your friend here.

What is the effective load on the motor?

What is the force exerted to move P a distance y?
Thus - what is the work done to do this?

What is the work done to raise the lift, and thus point A, a distance x?

The answer has a clue, and another method:
Unwinding the cable at 2m/s does not mean that P moves at 2m/s.
Remember that the motor moves with the lift. 2m/s is the rate the total length of cable increases.

You'll note that the answer, 0.5ms, is exactly a quarter of 2m/s.
How many cables are pulling on the lift?
If the total length of cable increases by 2m/s, how much does each length of cable increase by?
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top