Finding the dipole moment of a molecule in an electric field

AI Thread Summary
The discussion revolves around calculating the dipole moment of a molecule subjected to an electric field. The energy required to reverse the dipole's orientation is given as 3.5x10^(-27) J, and the electric field strength is 1.8 kN/C. Participants clarify that the energy change corresponds to the difference in potential energy, which involves the angles of alignment (theta) of the dipole in the field. The correct formula for the change in potential energy is confirmed to include the negative sign, emphasizing the need to account for the initial and final angles. The conversation highlights the confusion around applying the equations correctly due to missing parameters like charge and distance.
Les talons
Messages
28
Reaction score
0

Homework Statement


"A molecule has its dipole moment aligned with a 1.8 kN/C electric field. If it takes 3.5x10^(-27) J to reverse the molecule's orientation, what is its dipole moment?"


Homework Equations


Potential energy of dipole in an electric field
U = -p*E = -p*E*cos(theta)

U = 0 corresponds to the dipole aligned at right angles to the field

Torque on a dipole in an electric field
tau = p X E

Dipole moment vector is the product of the equal and opposite charges separated by distance d
p = qd



The Attempt at a Solution


Greetings. My solution attempt is as follows:
U = -p*E
energy required to reverse dipole's orientation = potential energy of the dipole
From this I found:
-3.5x10^(-27) J /1.8 kN/C = -1.9x10^-30 C-m
But this is wrong and I don't know why. The dimensional analysis shows the correct units using this approach.
Then I tried to included the cos(theta) for the magnitude of the dot product, taking theta as pi because the dipole has to have its orientation reversed, and this produced the answer 1.9x10^-30 C-m, which is also incorrect.

I assume that the dipole has no kinetic energy since it is not described as moving, so the energy needed to reverse it's orientation must be large enough to equal its potential energy. This energy has to be applied by doing work on the dipole, which is given, but since there are no charges or distance given, I cannot use p = qd. Then because I don't have p, the torque equation does not help. I must be overlooking something really simple. There are no examples like this in my book. The ones I have found on other sites all show the approach that I tried, so they are no help. The professor did not discuss dipole moments in lecture and none of his slides have a calculation of it, but do show finding the electric field generated by a dipole, which does not work since the problem does not give a charge, q.

If anybody has any comments or ideas, they would be greatly appreciated. Cheers.
 
Physics news on Phys.org
Hello, Les talons. Welcome to PF!

Les talons said:
My solution attempt is as follows:
U = -p*E
energy required to reverse dipole's orientation = potential energy of the dipole

That's not quite right. The energy required is equal to the change in potential energy of the dipole.

What are the initial and final values of θ?
 
Thank you for answering. There are no values given so does that mean we can assign our own coordinate system? Initially, the dipole is aligned, so theta = 0, and at the final position the dipole moves orientation, so theta = pi. I do know at theta = pi/2 the dipole will have U = 0. Would this be the right formula for the change in U: p*E*cos(theta_final) -p*E*cos(theta_initial)?
 
Last edited:
Les talons said:
Initially, the dipole is aligned, so theta = 0, and at the final position the dipole moves orientation, so theta = pi. I do know at theta = pi/2 the dipole will have U = 0.

Right.

Would this be the right formula for the change in U: p*E*cos(theta_final) -p*E*cos(theta_initial)?

Yes, except don't forget that there is a negative sign in the expression for U:
U = -pEcosθ
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top