Electric field of a charged rod

AI Thread Summary
To find the electric field at the center of a semicircular rod of charge, start by considering the symmetry of the problem, where the y-components of the electric field will cancel out, leaving only the x-components. The electric field due to a small arc length can be calculated using Coulomb's law, with the charge of that segment determined by its length and the total charge distributed along the rod. The radius of the semicircle, R, is crucial for determining the distance in the electric field equation, E = kq/r, where q is the charge of the small segment. Integration over the semicircle will yield the total electric field at the center. A clear diagram and careful calculations will aid in solving the problem effectively.
twiztidmxcn
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hey

just looking for some help on an electric field question involving a rod of charge. here's the problem:

You have a charge, Q, uniformly distributed along a thin, flexible rod with length L. The rod is then bent into a semi-circle.

a) Find expression for electric field at center of semicircle
b) Evaluate field strength if L = 10cm, Q = 30nC.

The rod starts out straight and is then bent into a half circle.

We are also given the hint that: A small piece of arc length delta-s spans a small angle delta-theta = delta-s / R , where R is the radius.

Now, I realize that this problem has lots of symmetry, mostly where the x and y components of the electric field are concerned. I know that all the y components will cancel due to this symmetry and all that we're left with are the x components.

I'm attempting to use the equation of a rod of charge to derive something for the circle, but I am a bit stuck. Basically, I'm stuck at E = kq/r, r hat.

I believe that I can just use that equation, find r in terms of x and y (using triangles, pythagorean theorem) and then integrate in terms of x. I'm not quite sure about this though...

Any sort of help in the right direction would be much appreciated.

thanks
twiztidmxcn
 
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