Find the Electric Field strength

AI Thread Summary
To find the electric field strength in a copper cable carrying a 50A current with a radius of 0.003m and a resistivity of 1.7x10^-8 Ohm/m, the current density (J) can be calculated using the formula J = I/A, where A is the cross-sectional area. The relationship between current density and electric field is expressed through Ohm's law, J = σE, where σ is the conductivity. The resistivity can be converted to conductivity using σ = 1/ρ. By substituting the values into the equations, the electric field strength can be determined. The discussion emphasizes the application of Ohm's law and the work-energy theorem in solving the problem.
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Homework Statement


"A copper cable carrying 50A current has radius 0.003m. What is the electric field if copper has a resistivity of 1.7x10^-8 Ohm/m?"

Homework Equations


Formula for current density etc.

The Attempt at a Solution



So I write:
\vec{\mathbf{J}} = n|q|v_d = \frac{I}{A}

And then:
\vec{\mathbf{J}} \cdot \rho = \frac{I}{A} \cdot \frac{RA}{L} = \frac{V}{L}

And now do I just apply the work energy theorem?:
\int \vec{\mathbf{E}} \cdot d\vec{\mathbf{l}} = \Delta V_{ab}

It kind of feels as though I'm completely off tbh...
 
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Use Ohm's law \mathbf{J}=\sigma \mathbf{E}.
 
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