Calculating Inside Diam. & Stress of Hollow Steel Shaft

AI Thread Summary
The discussion focuses on calculating the inside and outside diameters of a hollow steel shaft subjected to a torque of 5400 Nm and a torsional shear stress of 150 MPa. The calculated diameters are 64.49 mm for the outside and 48.37 mm for the inside. The participant is uncertain about the correct formula to determine the stress on the inside of the shaft and attempts to use the formula 16T/(πd^3). It is clarified that the polar moment of inertia (J) for a hollow shaft is calculated using J = (π/32)(d_outer^4 - d_inner^4). The calculated stress of 243 MPa exceeds the allowable limit of 150 MPa, indicating a potential design issue.
darkmagic
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Homework Statement



Given:
hollow steel shaft
Torque = 5400 Nm
Torsional Shear = 150 MPa

Required:
Inside diameter
Outside Diameter
Stress on the inside of the shaft

Homework Equations





The Attempt at a Solution


I solved both the diameters which are 64.49 mm and 48.37 mm.
I don't know what formula to use to determine the stress on the inside of the shaft

I used to 16T/[pi d^3) where d is the inside diameter. Am I correct?
 
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T/J = (shear stress)/r

so shear stress = Tr/J

at the outer, r = outer radius

at the inner r = inner radius
 
The J and r are already substituted in the formula I used. Ok thanks.
 
Is J there the J of the smaller circle, with the inside diameter? I got 243 Mpa which is larger than 150 Mpa.
 
darkmagic said:
Is J there the J of the smaller circle, with the inside diameter? I got 243 Mpa which is larger than 150 Mpa.

Your shaft is a hollow one, so the J = (π/32)(douter4-dinner4)
 
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