Troubleshooting Electric Flux Calculation on a Square Surface

AI Thread Summary
The user is struggling with calculating electric flux through a square surface using the formula (E * Area * cos(theta)) and obtained an incorrect result of 0.02529. The square surface measures 4.0 mm per side and is in an electric field of 1930 N/C at a 35° angle to the normal. There is confusion regarding the angle used in the calculation, as one participant suggests using 55° instead of 35°. The discussion also touches on whether electric flux can be negative, depending on the direction of the electric field relative to the surface. The lack of a visual representation of the problem is noted as a potential issue in understanding the scenario.
Rave Grrl
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I used the formula (E * Area * cos(theta)) and got the wrong answer (.02529) and I really don't understand why. I need help

The square surface shown measures 4.0 mm on each side. It is immersed in a uniform electric field with magnitude E = 1930 N/C. The field lines make an angle of 35° with a normal to the surface, as shown. Take the normal to be "outward," as though the surface were one face of a box. Calculate the electric flux through the surface.
 
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It looks correct (probably not the final #).U may have to check the units (\left(1\mbox{mm})\right)^{2}=10^{-6} \mbox{m}^{2}...

Daniel.
 
35 degrees to the normal is 55 degrees to the surface. Did you try that?
 
Halls,she needs the scalar product between the electric field vector and the normal to the surface,which make an angle of 35° between them...

Daniel.
 
I tried 55, and it didn't work.

Is electrical flux supposed to be negative? Thats all I can think of. I don't know if that's right.
 
Depends on the sense of the electric field.If it enters the page or not.Your problem is pretty vague in this issue,because you haven't provided the drawing/picture.

Daniel.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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