Where Did I Go Wrong in Finding the Net Charge on a Sphere?

AI Thread Summary
The discussion focuses on calculating the net charge on a conducting solid sphere based on the electric field measured outside it. The electric field at 15 cm from the center is given as 3.0E3 N/C, directed inward, indicating a negative charge on the sphere. The formula used for the electric field outside a charged sphere is E = kQ/r^2, where k is Coulomb's constant. The error in the initial calculation likely stems from incorrect arithmetic or using the wrong formula. The correct approach confirms that the sphere behaves like a point charge, and the net charge can be determined by rearranging the formula accordingly.
mr_coffee
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An unkown charge sits on a conducting solid sphere of radius 10 cm. If the E-field 15cm from the center of the sphere has the magnitude 3.0E3 N/c and is directed radiually inward, what is the net charge on the sphere? I used
E = q/(4PIEoR^2) plugged and chugged and got 3.34E-9 which isn't right of course, where did i screw up?
 
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Are you sure you're not doing the arithmetic incorrectly? I got a different numeric answer. Post what numbers you used in your calculation.
 
For an outside point w.r.t the charged solid sphere , the solid sphere behaves like a point charge , so assume solid sphere to be a point charge with charge Q , now electric field at a distance 'r' outide this solid sphere(point charge) is given by:

<br /> E= \frac{kQ}{r^2}<br />

You just need to fill in the values to calculate Q.Since the field is inwards, the charge will be negative.

BJ
 
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