As the title suggests, I have to prove, if (X, d) is a metric space, that for any subset A of X, diam A = diam Cl(A), i.e. the diameter of A equals the diameter of its closure.
So, if A is closed, it is trivial, since Cl(A) = A. Assume A is open. Now I'm a bit lost.
If A is open in (X, d)...