Operators Definition and 1000 Threads
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A Functional Determinant of a system of differential operators?
So in particular, how could the determinant of some general "operator" like $$ \begin{pmatrix} f(x) & \frac{d}{dx} \\ \frac{d}{dx} & g(x) \end{pmatrix} $$ with appropriate boundary conditions (especially fixed BC), be computed? And assuming that it diverges, would it be valid in a stationary...- Yellotherephysics
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- Determinant Differential Functional Functional analysis Operators Path integral Path integral formulation Path integrals System
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- Forum: Quantum Physics
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A Converting between field operators and harmonic oscillators
Suppose we have a Hamiltonian containing a term of the form where ∂=d/dr and A(r) is a real function. I would like to study this with harmonic oscillator ladder operators. The naïve approach is to use where I have set ħ=1 so that This term is Hermitian because r and p both are.*...- SupernerdSven
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- Field Field operators Harmonic Hermitian Operators Oscillators Quantum field theory Quantum harmonic oscillator
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- Forum: Quantum Physics
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B Reconciling basis vector operators with partial derivative operators
Ref. 'Core Principles of Special and General Relativity' by Luscombe. Apologies in advance for the super-long question, but it's necessary to show my thought process. Let ##\gamma:I\to M## be a smooth curve from an open interval ##I\subset\mathbb{R}## to a manifold ##M##, and let...- Shirish
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- Basis Derivative Operators Partial Partial derivative Vector
- Replies: 4
- Forum: Differential Geometry
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I Quantum operators and trasformation under rotations
Good morning! I have a problem in understanding the steps from vectors to operators. Imagine you are given a vectorial observable. In classical mechanics, after rotating the system it transform with a rotation matrix R. If we go to quantum mechanics, this observable becomes an operator that is...- forever_physicist
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- Operators Quantum Rotations
- Replies: 3
- Forum: Quantum Physics
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Quantum Hilbert spaces and quantum operators being infinite dimensional matrices
I just realized quantum operators X and P aren't actually just generalizations of matrices in infinite dimensions that you can naively play with as if they're usual matrices. Then I learned that the space of quantum states is not actually a Hilbert space but a "rigged" Hilbert space. It all...- AndreasC
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- Hilbert Hilbert spaces Infinite Matrices Operators Quantum
- Replies: 27
- Forum: Science and Math Textbooks
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I Quantum Field Operators for Bosons
Consider the field creation operator ψ†(x) = ∫d3p ap†exp(-ip.x) My understanding is that this operator does not add particles from a particular momentum state. Rather it coherently (in-phase) adds a particle created from |0> expanded as a superposition of momentum eigenstates states...- knowwhatyoudontknow
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- Bosons Field Field operators Operators Quantum
- Replies: 4
- Forum: Quantum Physics
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B Question about squares of operators
The magnitude of the momentum ##p## satisfies ##p^2 = p_x^2 + p_y^2 + p_z^2## and this implies the operator equation ##\hat{p}^2 = \hat{p}_x^2 + \hat{p}_y^2 + \hat{p}_z^2##, so we can say that ##\hat{p}^2 = -\hbar^2 (\frac{\partial^2}{\partial x^2} + \frac{\partial^2}{\partial y^2} +...- etotheipi
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- Operators Squares
- Replies: 17
- Forum: Quantum Physics
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I Finding matrices of perturbation using creation/annihilation operators
"Given a 3D Harmonic Oscillator under the effects of a field W, determine the matrix for W in the base given by the first excited level" So first of all we have to arrange W in terms of the creation and annihilation operator. So far so good, with the result: W = 2az2 - ax2 - ay2 + 2az+ 2 -ax+...- Keru
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- Matrices Operators Perturbation
- Replies: 3
- Forum: Quantum Physics
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Annihilation operators of two different types of Fermions
IfA=cd, where c and d are annihilation operators of two different types of Fermions, then {A,A°}is? A.1+n1+n2 B.1-n1+n2 C.1-n2+n1 D.1-n1-n2 Where,n1 and n2 are corresponding number operator, A° means A dagger or creation operator,as the particles are fermions they will obey anti-commutation I think- Tanmoy
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- Annihilation Fermions Operators
- Replies: 3
- Forum: Advanced Physics Homework Help
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A Algebraic form of Klein Gordon ##\phi^4## vacuum and ladder operators
In theory, does an algebraic expression exist for the ground state of the Klein Gordon equation with \phi^4 interactions in the same way an algebraic expression exists for the simple harmonic oscillator ground state wavefunction in Q.M.? Is it just that it hasn't been found yet or is it...- QFT1995
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- Form Klein Ladder operators Operators Vacuum
- Replies: 5
- Forum: Quantum Physics
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I Creation/annihilation operators question
I've recently stumbled upon something that looked kind of silly, but I still find myself a bit confused by it. Namely in quantum field theory, when we quantize a scalar field, we impose commutation relations on creation and annihilation operators that correspond to momenta in their mode...- Antarres
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- Operators
- Replies: 5
- Forum: Quantum Physics
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Working out harmonic oscillator operators at ##L \rightarrow \infty##
Let's go step by step a) We know that the harmonic oscillator operators are $$a^{\dagger} = \frac{1}{\sqrt{2 \hbar m \omega}} ( -ip + m \omega q)$$ $$a= \frac{1}{\sqrt{2 \hbar m \omega}} (ip + m \omega q)$$ But these do not depend on ##L##, so I guess these are not the expressions we want...- JD_PM
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- Harmonic Harmonic oscillator Operators Oscillator
- Replies: 11
- Forum: Advanced Physics Homework Help
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A What Conditions Allow the Derivative Trick for Evaluating Fermionic Commutators?
I found a theorem that states that if A and B are 2 endomorphism that satisfies $$[A,[A,B]]=[B,[A,B]]=0$$ then $$[A,F(B)]=[A,B]F'(B)=[A,B]\frac{\partial F(B)}{\partial B}$$. Now I'm trying to apply this result using the creation and annihilation fermionics operators $$B=C_k^+$$ and $$A=C_k$$...- thetafilippo
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- Commutator Commutators Conditions Differentiation Operators
- Replies: 4
- Forum: Quantum Physics
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A Commutation relations between HO operators | QFT; free scalar field
I am getting started in applying the quantization of the harmonic oscillator to the free scalar field. After studying section 2.2. of Tong Lecture notes (I attach the PDF, which comes from 2.Canonical quantization here https://www.damtp.cam.ac.uk/user/tong/qft.html), I went through my notes...- JD_PM
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- Commutation Field Operators Qft Relations Scalar Scalar field
- Replies: 10
- Forum: Quantum Physics
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Harmonic Oscillator Ladder Operators - What is (ahat_+)^+?
I know that ahat_+ = 1/sqrt((2*m*h_bar*w)) * (mw(xhat)+i(phat)) and ahat_- = 1/sqrt((2*m*h_bar*w)) * (mw(xhat)-i(phat)). But I'm not sure what (ahat_+)^+ could be.- gabriellelee
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- Harmonic Harmonic oscillator Ladder operators Operators Oscillator
- Replies: 1
- Forum: Advanced Physics Homework Help
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Linear operators, quantum mechanics
Hello, I am struggling with what each piece of these equations are. I generally know the two rules that need to hold for an operator to be linear, but I am struggling with what each piece of each equation is/means. Lets look at one of the three operators in question. A(f(x))=(∂f/∂x)+3f(x) I...- cookiemnstr510510
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- Linear linear operators Mechanics Operators Quantum Quantum mechanics
- Replies: 12
- Forum: Advanced Physics Homework Help
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I Is there a reason eigenvalues of operators correspond to measurements?
Given a wave function \Psi which is an eigenstate of a Hermitian operator \hat{Q}, we can measure a definite value of the observable corresponding to \hat{Q}, and the value of this observable is the eigenvalue Q of the eigenstate $$ \hat{Q}\Psi = Q\Psi $$ My question is whether it's a postulate...- gsingh2011
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- Eigenvalues Measurements Operators Reason
- Replies: 2
- Forum: Quantum Physics
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Deriving commutator of operators in Lorentz algebra
Li=1/2*∈ijkJjk, Ki=J0i,where J satisfy the Lorentz commutation relation. [Li,Lj]=i/4*∈iab∈jcd(gbcJad-gacJbd-gbdJac+gadJbc) How can I obtain [Li,Lj]=i∈ijkLk from it?- YSM
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- Algebra Commutator deriving Lorentz Operators Qft
- Replies: 1
- Forum: Advanced Physics Homework Help
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I Raising and Lowering Operators
Why is it that the raising and lowering operators in a spin 1/2 system have a factor of $\hbar ?$ From Sakurai: $$S_+ \equiv \hbar | + \rangle \langle - |, S_- \equiv \hbar | - \rangle \langle + |$$ "So the physical interpretation of $S_+$ is that it raises the component by one unit of $\hbar...- aliens123
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- Operators
- Replies: 2
- Forum: Quantum Physics
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Landau levels: Hamiltonian with ladder operators
Dear PF, I hope I've formulated my question understandable enough. Thank you for your time, Garli- Garlic
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- Angular momentum operator Hamiltonian Ladder operator Ladder operators Landau Levels Operators
- Replies: 1
- Forum: Advanced Physics Homework Help
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A Do the time and normal ordering operators commute?
Does the time ordering operator ##\mathcal{T}## commute with the normal ordering operator ##\hat{N}##? i.e. is $$[ \mathcal{T},\hat{N}] =0$$ correct?- QFT1995
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- Commute Normal Operators Time
- Replies: 11
- Forum: Quantum Physics
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I Condition for delta operator and total time differential to commute
While deriving continuity equation in Fluid mechanics, our professor switched the order of taking total time derivative and then applying delta operator to the function without stating any condition to do so(Of course I know it is Physics which alows you to do so) . So,I began to think...- Abhishek11235
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- Algebra Commute Condition Delta Differential Operator Operators Time
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- Forum: Classical Physics
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A Creation/annihilation operators and trigonometric functions
Hello everyone, I have noticed a striking similarity between expressions for creation/annihilation operators in terms position and momentum operators and trigonometric expressions in terms of exponentials. In the treatment by T. Lancaster and S. Blundell, "Quantum Field Theory for the Gifted...- jshtok
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- Functions Operators Trigonometric Trigonometric functions
- Replies: 9
- Forum: Quantum Physics
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I Hermitian operators in QM and QFT
I have always learned that a Hermitian operator in non-relativistic QM can be treated as an "experimental apparatus" ie unitary transformation, measurement, etc. However this makes less sense to me in QFT. A second-quantised EM field for instance, has field operators associated with each...- WWCY
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- Hermitian Operators Qft Qm
- Replies: 7
- Forum: Quantum Physics
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A Explicit form of annihilation and creation operators for Dirac field
I'm unclear on what exactly an annihilation or creation operator looks like in QFT. In QM these operators for the simple harmonic oscillator had an explicit form in terms of $$ \hat{a}^\dagger = \frac{1}{\sqrt{2}}\left(- \frac{\mathrm{d}}{\mathrm{d}q} + q \right),\;\;\;\hat{a} =...- QFT1995
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- Annihilation Creation Dirac Dirac field Explicit Field Form Operators
- Replies: 6
- Forum: Quantum Physics
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I Why observables are represented as operators in QM?
Can somebody provide an explanation why the dynamical variables/observables are represented in QM as linear operators with the measured values being eigenvalues of these operators? For energy this is probably trivially and directly follows from the stationary Shrodinger equation which solutions...- MichPod
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- observables Operators Qm
- Replies: 4
- Forum: Quantum Physics
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I Understanding Operators in Matrix Mechanics
I'm trying to understand some notes that I have been given on Matrix Mechanics, specifically how the matrix element comes about and builds a matrix which when used applies the effect of an operator on a wavefunction. But I'm having some difficulties following what's being done in the notes with...- Avardia
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- Matrix Mechanics Operators
- Replies: 1
- Forum: Quantum Physics
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I Multiplying two function operators
I am reading Zettili’s “Quantum Mechanics: Concepts and Applications” and I am in the section on functions of operators. It starts with how ##F(\hat A)## can be Taylor expanded and gives the particular and familiar example: $$e^{a \hat A} = \sum_{n=0}^\infty \frac{a^n}{n!} \hat A^n...- Pencilvester
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- Function Operators
- Replies: 10
- Forum: Quantum Physics
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I Boundary terms for field operators
Hello! In several of the derivations I read so far in my QFT books (M. Schawarz, Peskin and Schroeder) they use the fact that "we can safely assume that the fields die off at ##x=\pm \infty##" in order to drop boundary terms. I am not sure I understand this statement in terms of QFT. A field in...- kelly0303
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- Boundary Field Field operators Operators Terms
- Replies: 17
- Forum: High Energy, Nuclear, Particle Physics
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I Quantum Computing - projection operators
Assume ##P_1## and ##P_2## are two projection operators. I want to show that if their commutator ##[P_1,P_2]=0##, then their product ##P_1P_2## is also a projection operator. My first idea was: $$P_1=|u_1\rangle\langle u_1|, P_2=|u_2\rangle\langle u_2|$$ $$P_1P_2= |u_1\rangle\langle...- Peter_Newman
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- Commutator Computing Operators Projection Quantum Quantum computation Quantum computing
- Replies: 16
- Forum: Quantum Physics
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Expectation value of operators and squeezing in the even cat state
I started and successfully showed that the expectation of X_1 and X_2 are zero. However the expectation value of X1^2 and X2^2 which I am getting is <X1^2> = 0.25 + \alpha^2 and <X2^2> = 0.25. How do I derive the given equations?- eigenpsi
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- even Expectation Expectation value Linear algebra Operator Operators Quantum optics Quantum phyics squeezing State Uncertainty principle Value
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- Forum: Advanced Physics Homework Help
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Ladder Operators: Commutation Relation & Beyond
a. ##L_{+}^{\dagger}=(L_x+iL_y)^{\dagger}=L_x-iL_y=L_{-}## b.##[L_{+},L_{-}]=[L_x+iL_y,L_x-iL_y]=(L_x+iL_y)(L_x-iL_y)-(L_x-iL_y)(L_x+iL_y)=## ##=L_x^2-iL_xL_y+iL_yL_x+L_y^2-(L_x^2+iL_xL_y-iL_yL_x-L_y^2)## ##=L_x^2-iL_xL_y+iL_yL_x+L_y^2-L_x^2-iL_xL_y+iL_yL_x+L_y^2##...- Gbox
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- Ladder operators Operators
- Replies: 1
- Forum: Advanced Physics Homework Help
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I Do spin operators 'appear' to commute for an entangled spin state?
Let's consider Bohm's paradox (explaining as follows). A zero spin particle converts into two half-spin particles which move in the opposite directions. The parent particle had no angular momentum, so total spin of two particles is 0 implying they are in the singlet state. Suppose we measured Sz...- muonion
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- Commute Entangled Entanglement Operators Spin State
- Replies: 4
- Forum: Quantum Physics
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I Projection Operators: Pi, Pj, δij in Quantum Mechanics
In Principles of Quantum mechanics by shankar it is written that Pi is a projection operator and Pi=|i> <i|. Then PiPj= |i> <i|j> <j|= (δij)Pj. I don't understand how we got from the second result toh the third one mathematically.I know that the inner product of i and j can be written as δijbut...- RohanJ
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- Operators Projection
- Replies: 3
- Forum: Quantum Physics
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I Derivative operators in Galilean transformations
I'm studying how derivatives and partial derivatives transform under a Galilean transformation. On this page: http://www.physics.princeton.edu/~mcdonald/examples/wave_velocity.pdf Equation (16) relies on ##\frac{\partial t'}{\partial x}=0## but ##\frac{\partial x'}{\partial t}=-v## But this...- TomServo
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- Derivative Galilean Operators Transformations
- Replies: 5
- Forum: Classical Physics
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I Pauli exclusion principle and Hermitian operators
http://vergil.chemistry.gatech.edu/notes/quantrev/node20.html "Postulate 2. To every observable in classical mechanics there corresponds a linear, Hermitian operator in quantum mechanics. " "Postulate 6. The total wavefunction must be antisymmetric with respect to the interchange of all...- jlcd
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- Hermitian Operators Pauli Pauli exclusion principle Principle
- Replies: 15
- Forum: Quantum Physics
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Show the formula which connects the adjoint representations
That's my attempting: first I've wrote ##e## in terms of the power series, but then I don't how to get further than this $$ \sum_{n=0}^\infty (-1)^n \frac {Â^n} {n!} \hat B \sum_{n=0}^\infty \frac {Â^n} {n!} = \sum_{n=0}^\infty (-1)^n \frac {Â^2n} {\left( n! \right) ^2} $$. I've alread tried to...- Mutatis
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- Formula Operator Operators Power series Representations
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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The position and momentum operators for a free particle in Heisenberg picture
Homework Statement From Griffiths GM 3rd p.266 Consider a free particle of mass ##m##. Show that the position and momentum operators in the Heisenberg picture are given by$$ {\hat x}_H \left( t \right) ={\hat x}_H \left( 0 \right) + \frac { {\hat p}_H \left( 0 \right) t} m $$ $$ {\hat p}_H...- Haorong Wu
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- Free particle Heisenberg heisenberg picture Momentum Operators Particle Picture Position
- Replies: 2
- Forum: Advanced Physics Homework Help
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I Confusion about the Concept of Operators
Dear all, I've been reading and got confused of the concept below have two questions question 1) For <ψ|HA|ψ> = <Hψ|A|ψ>, why does the Hamiltonian operator acting on the bra state and <ψ|AH|ψ> in this configuration it will act on the ket state? question 2) what does it mean for H|ψ> = |Hψ>...- jdou86
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- Concept Confusion Operator Operators Quantum mechanics
- Replies: 14
- Forum: Quantum Physics
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I Symmetries in quantum mechanics and the change of operators
When we make a symmetrie transformation in a quantum system, the state ##|\psi \rangle## change to ## |\psi' \rangle = U|\psi \rangle##, where ##U## is a unitary or antiunitary operator, and the operator ##A## change to ##A'##. If we require that the expections values of operators don't change...- Lebnm
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- Change In quantum mechanics Mechanics Operators Quantum Quantum mechanics Symmetries
- Replies: 3
- Forum: Quantum Physics
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If A and B are Hermitian operators is (i A + B ) Hermitian?
If A and B are Hermitian operators is (i A + B ) a Hermitian operator? (Hint: use the definition of hermiticity used in the vector space where the elements are quadratic integrable functions) I know an operator is Hermitian if: - the eigenvalues are real - the eigenfunction is orthonormal -...- Settho
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- Hermitian Operators
- Replies: 4
- Forum: Advanced Physics Homework Help
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Spin Annhilation and Creator Operators Matrix Representation
Homework Statement Given the expression s_{\pm}|s,m> = \hbar \sqrt{s(s+1)-m(m\pm 1)}|s,m \pm 1> obtain the matrix representations of s+/- for spin 1/2 in the usual basis of eigenstates of sz Homework Equations s_{\pm}|s,m> = \hbar \sqrt{s(s+1)-m(m\pm 1)}|s,m \pm 1> S_{+} = \hbar...- TheBigDig
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- Matrix Operators Quantum mechahnics Representation Spin Spin 1/2
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- Forum: Introductory Physics Homework Help
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I Annihilation vs. Creation Operators: What's the Difference?
Cohererent states are defined as eigenstates of the annihilation operator. Never the creation operator is referred to. Is this just a convention or is more behind? What is the essential difference between eigenstates of the annihilation- versus the creation operator? Thank you very much in...- gerald V
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- Annihilation Creation Difference Operators
- Replies: 3
- Forum: Quantum Physics
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I Multiplication of ladder-operators
Hi! When calculating ##(\hat{a} \hat{a}^{\dagger})^2## i get ##\hat{a} \hat{a} \hat{a}^{\dagger} \hat{a}^{\dagger}## which is perfectly fine. But how do I end up with the ultimate simplified expression $$\hat{ a}^{\dagger} \hat{a} \hat{a}^{\dagger} \hat{a} + \hat{a}^{\dagger} \hat_{a} +...- Philip Land
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- Multiplication Operators Quantum mechahnics
- Replies: 1
- Forum: Quantum Physics
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B Gradient and divergence operators
One way to get the gradient of polar coordinates is to start from the Cartesian form: ##\nabla = \hat x \frac{\partial}{\partial x} + \hat y \frac{\partial}{\partial y}## And then to use the following four identies: ##\hat x = \hat r\cos\theta - \hat{\theta}\sin\theta## ##\hat y = \hat... -
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I Raising the ladder operators to a power
Hi! I am working on homework and came across this problem: <n|X5|n> I know X = ((ħ/(2mω))1/2 (a + a+)) And if I raise X to the 5th, its becomes X5 = ((ħ/(2mω))5/2 (a + a+)5) What I'm wondering is, is there anyway to be able to solve this without going through all of the iterations the...- MooshiS
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- Ladder operator Ladder operators Lowering operator Operators Power Quantum Raising operator
- Replies: 3
- Forum: Quantum Physics
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A Operators used without being explained
I started watching the video lecture series here: https://ocw.mit.edu/courses/physics/8-04-quantum-physics-i-spring-2016/video-lectures/part-1/ I notice that they use the term "operator" without first explaining it. Operators are also not explained (in fact they are not even mentioned) in my...- Technon
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- Operators
- Replies: 4
- Forum: Quantum Physics
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I Does a Quantum Field Creation Operator Create Particles at a Given Location?
Hi, It appears that the definition of a quantum field creation operator is given by $$\Psi^{\dagger}(\mathbf r) = \sum\limits_{\mathbf k} e^{-i\mathbf k\cdot \mathbf r} a^{\dagger}_{\mathbf k}.$$ But then if we examine how this operator acts on the vacuum state, we get $$\Psi^{\dagger}(\mathbf...- acegikmoqsuwy
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- Field Field operators Operators Quantum
- Replies: 1
- Forum: Quantum Physics
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Prove formula for the product of two exponential operators
Homework Statement Consider two operators A and B, such that [A,[A, B]] = 0 and [B,[A, B]] = 0 . Show that Exp(A+B) = Exp(A)Exp(B)Exp(-1/2 [A,B]) Hint: define Exp(As)Exp(Bs) as T(s), where s is a real parameter, differentiate T(s) with respect to s, and express the result in terms of T(s)...- astrocytosis
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- Commutators Exponential Formula Operators Product
- Replies: 2
- Forum: Advanced Physics Homework Help
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I Gluon creation and annihilation operators
Hi, When one quantizes EM the resulting gauge boson, the photon, ends up being its own antiparticle. From what I read of gluons, they have anti particles. I can follow how anti particles come about quantizing a complex-valued field like that for electrons. For the spin 1/2 case non-interacting...- Paul Colby
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- Annihilation Creation Gluon Gluons Operators
- Replies: 4
- Forum: High Energy, Nuclear, Particle Physics