Resistance from Microscopic Ohm's law

AI Thread Summary
The discussion focuses on calculating the resistance of a cylindrical resistor made from a conductive material with conductivity σ. The resistance R is derived using Ohm's Law, starting from the relationships between current density J, electric field E, and the definitions of voltage and current. The final expression for resistance is simplified to R = L/(σA), where L is the length and A is the cross-sectional area of the resistor. Participants clarify the cancellation of electric field terms in the calculations. The conversation emphasizes the importance of correctly applying the principles of Ohm's Law to derive the resistance formula.
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Homework Statement



Your task is to calculate the resistance of a simple cylindrical resistor with wires connected to the ends, such as the carbon composition resistors that are used on electronic circuit boards. Imagine that the resistor is made by squirting material whose conductivity is \sigma into a cylindrical mold with length L and cross-sectional area A. Assume that this material satisfies Ohm's law. (It should if the resistor is operated within its power dissipation limits.)

What is the resistance R of this resistor?
Express the resistance in terms of variables given in the introduction. Do not use V or I in your answer.

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Homework Equations



J=\SigmaE
V=EL
I=JA
R = V/I

The Attempt at a Solution



I start out with Ohm's Law and get resistence R to be R = V/I and I know V = EL and I = JA so I get resistence R to be R = EL/JA. I also know J = \SigmaE. So I get resistence R to be R = EL/\SigmaEA

Would the two E's cancel out?
 
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I will continue from your R = EL/JA expression.
J = \sigmaE
therefore,
R = EL/\sigmaEA
the E's cancel out and your answer should be R = L/\sigmaA

Hope this helps.
 
Ah, wrong sigma. Got it, thanks.
 
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