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3 phase power systems: per unit with transformers

  1. Mar 23, 2016 #1
    • Member advised to use the formatting template for questions posted to the homework forums
    Hey,

    I'm currently working a problem that looks like this:

    Capture.PNG

    There's more to this problem, but I'm sure I can solve the rest of it, there are just things I'm uncertain about. Actually, it's only one thing I'm uncertain about.

    I'm looking through my notes, and when converting the voltage base at one bus to another, sometimes there's a conversion from line-to-line to line-to-neutral, and sometimes there's no conversion at all, just purely the transformer's coil ratios. I've looked through all these sample problems, and I cannot find a pattern of when to divide by sqrt 3 and when not to.

    I'm not sure if I've explained myself fully. For example, let's try to find the bases at bus 1:

    First, since there's no transformer between bus 2 and bus 3, we know their bases are the same:

    bus 2: 115kv, 132.25 ohms

    Now, find bus 1:

    The coil ratio is 115/14.4, and the low voltage side is at bus 1, with the high voltage side at bus 2. Thus, the voltage base at bus 1 is (14.4/115) * 115 = 14.4 kv. But, do I have to divide by sqrt 3 for some line-to-line to line-to-neutral conversion? That's what I'm really unsure about and need to understand for this material. Is the voltage base at bus 1 14.4kv or is it 8.31kv?

    I'd really appreciate some help on this subject and look forward to it.
     
  2. jcsd
  3. Mar 25, 2016 #2
    Hi Brian, Its a bit out of my field but I think I have spotted the clue. The only time you need to convert from line-to-line to line-to-neutral is when your transformer is connected in delta configuration on one side (eg the primary) and in star (or Y) configuration on the other side (eg the secondary). This information is given to you in the diagram of the transformers which have a little "∆" or "Y" written under each primary and secondary. When both the primary and secondary have the same symbol (ie both are Y or both are ∆), then you need no √3 conversion, but when they are different then you do need to convert. I imagine you can work out whether to step the voltage up or down in each case where they are different?
     
  4. Mar 26, 2016 #3
    This is one reason I considered -- but I found an example in my notes with a Y-delta configuration without the conversion. I've already submitted the assignment so by next lecture this answer should come to light, and I might post on here the reason why. Thanks for the reply
     
  5. Mar 26, 2016 #4
    I'll be willing to bet that your notes are incorrect in this case!
     
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