A neutral metal rod in a uniform magnetic field

Click For Summary
SUMMARY

A neutral metal rod of length 0.35 m slides at a constant speed of 9 m/s through a uniform magnetic field of 0.6 tesla. The net force on a mobile electron inside the rod is 0 N, while the magnetic force is calculated to be 8.64E-19 N. The electric force was incorrectly calculated as 8.64E-19 N, but the correct value is the absolute value, which is also 8.64E-19 N. The potential difference across the rod is determined to be 1.89 V.

PREREQUISITES
  • Understanding of electromagnetic forces, specifically Lorentz force
  • Familiarity with the concepts of electric fields and magnetic fields
  • Knowledge of potential difference and its calculation
  • Basic principles of electron behavior in magnetic fields
NEXT STEPS
  • Study the Lorentz force equation in detail
  • Learn about the relationship between electric and magnetic fields in conductive materials
  • Explore the concept of induced electromotive force (EMF) in moving conductors
  • Investigate the effects of varying magnetic field strengths on electron motion
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of charged particles in magnetic fields.

DeadFishFactory
Messages
25
Reaction score
0
21.X.091-moving-bar03.gif


Homework Statement



A neutral metal rod of length 0.35 m slides horizontally at a constant speed of 9 m/s on frictionless insulating rails through a region of uniform magnetic field of magnitude 0.6 tesla, directed into the page as shown in the diagram. Before answering the following questions, draw a diagram showing the polarization of the rod, and the direction of the Coulomb electric field inside the rod.

(A) After the initial transient, what is the magnitude of the net force on a mobile electron inside the rod?

(B) What is the magnitude of the electric force on a mobile electron inside the rod?

(C) What is the magnitude of the magnetic force on a mobile electron inside the rod?

(D) What is the magnitude of the potential difference across the rod?




Homework Equations


Fmag + F(e) = F
Fmag = qBV
dV = EdL

The Attempt at a Solution



(A) After the initial transient, what is the magnitude of the net force on a mobile electron inside the rod?
|Fnet|= 0 N (correct)
(B) What is the magnitude of the electric force on a mobile electron inside the rod?
|Fe|= 8.64E-19 N (incorrect)
(C) What is the magnitude of the magnetic force on a mobile electron inside the rod?
|Fmag|= 8.64E-19 N (correct)
(D) What is the magnitude of the potential difference across the rod?
|dV|= 1.89 V (correct)



Why am I getting the electric force wrong (all the others are correct)? If:


Fnet = 0, then:

Fmag + F(E) = 0, therefore:

F(E) = -Fmag, and when:

Fmag = 8.64E-19 N, then

F(E) = -8.64E-19 N, right?

How come it's not?
 

Attachments

  • 21.X.091-moving-bar03.gif
    21.X.091-moving-bar03.gif
    7.6 KB · Views: 1,016
Last edited:
Physics news on Phys.org
Wait a minute, I got it; the stupid thing wants to the ABSOLUTE VALUE.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
11
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 3 ·
Replies
3
Views
1K