A positive charge kept inside a conducting shell

AI Thread Summary
A positive point charge located off-center inside a conducting spherical shell induces a total charge of -q on the inner surface of the shell, according to Gauss's law. The discussion emphasizes that the surface charge density cannot be positive anywhere on the inner surface because this would create a potential difference, violating the condition of uniform potential in a conductor. Electric field lines must terminate at negative charges, ensuring that the inner surface remains negatively charged throughout. Any positive charge on the inner surface would lead to an unstable situation, as charges would move to neutralize the potential difference. Thus, the inner surface charge density must be negative everywhere.
Titan97
Gold Member
Messages
450
Reaction score
18

Homework Statement


A positive point charge q is located off-center inside a conducting spherical shell.We know from
Gauss’s law that the total charge on the inner surface of the shell is −q. Is the surface charge density negative over the entire inner surface?
Or can it be positive on the far side of the inner surface if the point charge q is close enough to the shell so that it attracts enough negative charge to the near side? Justify your answer.
Capture.PNG


Homework Equations


None

The Attempt at a Solution


The author asks the reader to think about the electric field lines.
Why isn't it possible? I can have electric field lines like these:
Capture2.PNG
 
Physics news on Phys.org
The field lines from +q must terminate at negative charges on the inner surface of the shell. Because it is a conducting shell it must have a single uniform potential (no static potential difference can be maintained in a conductor). So what would happen to your positive and negative charges on the conductor?
 
  • Like
Likes Titan97
If there is positive charge on the shell's inner surface, there will be electric field lines from the negative charge of inner shell to the positively charged part. But if that's the case, the potential difference between any two points will not be zero.
 
Titan97 said:
If there is positive charge on the shell's inner surface, there will be electric field lines from the negative charge of inner shell to the positively charged part. But if that's the case, the potential difference between any two points will not be zero.
Right, and that is an unstable situation for a conductor. The charges MUST move to combine and cancel unless some field working tangentially to the surface opposes their movement. It's akin to finding a hill of water on a lake :smile:
 
  • Like
Likes Titan97
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top