A rocket moving vertically -- Find the cosmonaut's weight

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The discussion revolves around calculating the weight of a cosmonaut in a rocket accelerating vertically at 22 m/s², with a mass of 90 kg. The relevant equation used is N = m(a + g), leading to a calculated weight of 2880 N. Participants clarify the distinction between solving a problem and recognizing the solution, emphasizing the importance of understanding the result. The conversation highlights the need for confidence in problem-solving, even when initial uncertainty is expressed. Ultimately, the cosmonaut's weight was successfully determined through the application of the correct physics principles.
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Homework Statement


A rocket during launch from the Earth's surface moves vertically with an acceleration of 22m / s ^ 2. Find the cosmonaut's weight inside the cabin if his mass is 90kg.

Homework Equations


The problem belongs to "Elasticity. Moving under the action of elastic force" chapter.
General gravity relating to man = 900N;
N - G = ma?
N = m(a+g)
N = 90*(22+10) = 2880 N

The Attempt at a Solution


No idea currently, trying to solve[/B]
 
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inv4lid said:

Homework Statement


A rocket during launch from the Earth's surface moves vertically with an acceleration of 22m / s ^ 2. Find the cosmonaut's weight inside the cabin if his mass is 90kg.

Homework Equations


The problem belongs to "Elasticity. Moving under the action of elastic force" chapter.
General gravity relating to man = 900N;
N - G = ma?
N = m(a+g)
N = 90*(22+10) = 2880 N

The Attempt at a Solution


No idea currently, trying to solve[/B]

What the definition of weight?
 
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What do you mean ”no idea”? You essentially solved it.
 
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Orodruin said:
What do you mean ”no idea”? You essentially solved it.
Just got it, ty anyway
 
Orodruin said:
What do you mean ”no idea”? You essentially solved it.

There's solving a problem and knowing you've solved it!
 
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PeroK said:
There's solving a problem and knowing you've solved it!
I think the two are the same (as long as you got it right). Hence the addition of the ”essentially” - the remaining step being to realize that what was computed was the sought quantity.
 
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Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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