Air pressure/atmosphere problem

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The discussion centers on calculating the height of the atmosphere under the assumption of uniform density and incompressibility. Using the formula P = ρgh, where atmospheric pressure is 1.013 x 10^5 Pa and air density is 1.29 kg/m³, a height of approximately 8012.97 meters is derived. Participants confirm this calculation and emphasize that gravitational acceleration (g) can be considered constant at that height. The problem highlights the challenges faced by students when encountering unfamiliar test questions. Overall, the discussion reinforces the importance of understanding the relationship between pressure, density, and height in atmospheric physics.
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1. How high would the atmosphere extend (assume P=0 at the top) if it were uniform density Pair - 1.29 kg/m3 and we assumed the air was incompressible (Patm = 1.013 x 10e5 Pa



2. maybe roh g h?



3. I don't have any idea where to start with this. There are a few ideas in there that i just don't know where my teacher is going. This is a test review and we did not have a question quite like this in the homework or notes./b]
 
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Think about what rho g h equals
 
if P = roh g h
1.013 x 10e5 pa= 1.29kg/m3 x 9.8m/s2 x h
h = 8012.97 m?
 
can anyone confirm if i am correct or incorrect on this?
 
It's correct. You ought also to have been told to assume g is constant to that height.
 
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