Analytical Problem with Coulomb's Law

Click For Summary

Homework Help Overview

The problem involves calculating the force between two beakers containing aqueous solutions with excess charge, using Coulomb's Law in a hypothetical scenario where the laws of nature differ from our own. The beakers are separated by a distance of 1.20 meters, and each contains a specific molarity of charge.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of charge based on molarity and volume, with some expressing uncertainty about the resulting force value. There are questions regarding potential arithmetic errors and the expected magnitude of the force.

Discussion Status

Some participants have provided guidance to recheck calculations and emphasized the importance of including units in results. There is an acknowledgment of the large values obtained, but no consensus on the correctness of the calculations has been reached.

Contextual Notes

Participants note that the charge values derived from the given molarity and volume appear reasonable, but the resulting force calculations are questioned for being excessively large. There is mention of using different calculators, which may have contributed to discrepancies in results.

antonisz
Messages
27
Reaction score
0

Homework Statement


Consider a parallel universe where the laws of nature as we know them are different, and aqueous solutions can have an excess charge. Two beakers are separated 1.20 meters and each contains 0.300 L of an aqueous solution of 6.40 × 10-6 M excess charge. One beaker has a net positive charge, and one beaker has a net negative charge. Calculate the force between the beakers using the formula below,

JKuLV1m.png


where F is force, ε0 is the permittivity constant and is equal to 8.85 × 10-12 C2/(N·m2)·, q1 is the charge contained in the first beaker, q2 is the charge contained in the second beaker, and r is the distance between the beakers. Note that 1 mole of charge is 96,485 C, and because one of the beakers contains a net negative charge, one q will be negative, and F will be negative. A negative F corresponds to an attractive force.

Homework Equations


JKuLV1m.png


The Attempt at a Solution


I found the charge on the solutions to be to be .1853 and -.1853. I did this by multiplying the molarity by the volume .300L and then 96468 C.

After getting those numbers, I plugged into the formula and got an insanely large number for the force, -2.31 x 109. I'm not sure if I'm not understanding the problem or if it is an arithmetic error.Thank you!
 
Physics news on Phys.org
antonisz said:
I found the charge on the solutions to be to be .1853 and -.1853. I did this by multiplying the molarity by the volume .300L and then 96468 C.

After getting those numbers, I plugged into the formula and got an insanely large number for the force, -2.31 x 109. I'm not sure if I'm not understanding the problem or if it is an arithmetic error.

You can expect the force to be crazy large, but not quite as large as that; your result looks to be about an order of magnitude too large to me, so recheck your calculation. Your numerical value for the charges looks okay. Be sure to always include units on any result values that you present! Otherwise the result will be determined to be meaningless by a marker...
 
Well, if that's the formula you are supposed to use, then yes, an insanely large number is what you will get. I do not know why you got -2.31 x 109. It's a little too large.

Also, please always remember units. They can remind you if you have forgotten anything, or done anything wrong.
 
Avatrin said:
Well, if that's the formula you are supposed to use, then yes, an insanely large number is what you will get. I do not know why you got -2.31 x 109. It's a little too large.

Also, please always remember units. They can remind you if you have forgotten anything, or done anything wrong.

Sorry, I did have the units on my scratch work.

I tried it on my TI-83+ and I got 2.14 x 108, so it must have been me using the google calculator!

Thank you everyone!
 
Funny, I get -2.14 x 108. Still big. Goes to show that excess charge is not to be made fun of.

This 96468 C/mol is Avogadro's number 6.02214E+23 / mol times electron charge 1.60217E-19 C and it's a huge number. One coulomb is an awful lot of charge.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
11
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
6
Views
9K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K