The drawing shows a rectangular block of glass (n = 1.52) surrounded by liquid carbon disulfide (n = 1.63). A ray of light is incident on the glass at point A with a = 36.0° angle of incidence. At what angle of refraction does the ray leave the glass at point B?
Please explain a way to reach the solution for this problem. I tried using the equation: n2*sin(36) / n1
pic: http://img128.imageshack.us/img128/900/13113445ga1.png [Broken]
The Attempt at a Solution
not sure why this would not work: sin(B) = n1/n2 * sin(a)
so, 1.63/1/52 * sin(36) comes to 39.1 degrees??
please correct me if this is incorrect. However, the answer doesn't seem to be accurate. This is the angle that is refracted from the glass at B correct?
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