Angular Acceleration of game show wheel

AI Thread Summary
The discussion revolves around calculating the average torque exerted on a game show wheel that starts with an angular speed of 1.22 rad/s and comes to rest after rotating 3/4 of a turn. The wheel's parameters include a radius of 0.71m and a mass of 6.4kg, leading to a moment of inertia of 1.613 kg*m². Using the conservation of rotational kinetic energy, the average torque is derived from the equation τ*θ = (1/2)*I*(ωf² - ω0²), resulting in a calculated torque of approximately 0.25 Nm. Participants express confusion about the problem but receive guidance on applying the conservation of energy principle to find the solution. The discussion concludes with appreciation for the assistance provided.
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A wheel on a game show is given an initial angular speed of 1.22 rad/s. It comes to rest after rotating through 3/4 of a turn. Find the average torque exerted on the wheel given that it is a disk of radius 0.71m and a mass 6.4kg.

I'm lost. I don't really know where to begin. I know the answer is going to be 0.25Nm but I just need some help getting on the right track. Any suggestions?
 
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tsdemers said:
A wheel on a game show is given an initial angular speed of 1.22 rad/s. It comes to rest after rotating through 3/4 of a turn. Find the average torque exerted on the wheel given that it is a disk of radius 0.71m and a mass 6.4kg.

I'm lost. I don't really know where to begin. I know the answer is going to be 0.25Nm but I just need some help getting on the right track. Any suggestions?
Use conservation of energy

Work done = \tau \Delta \theta = Energy available = \frac{1}{2}I\omega^2

AM
 
tsdemers said:
A wheel on a game show is given an initial angular speed of 1.22 rad/s. It comes to rest after rotating through 3/4 of a turn. Find the average torque exerted on the wheel given that it is a disk of radius 0.71m and a mass 6.4kg.

I'm lost. I don't really know where to begin. I know the answer is going to be 0.25Nm but I just need some help getting on the right track. Any suggestions?
From the problem statement:
{Disk Mass} = M = (6.4 kg)
{Disk Radius} = R = (0.71 m)
{Disk Moment of Inertia} = I = (1/2)*M*R2 = (1/2)*(6.4)*(0.71)2 = (1.613 kg*m2)
{Initial Disk Angular Speed} = ω0 = (1.22 rad/s)
{Final Disk Angular Speed} = ωf = (0.0 rad/s)
{Disk Angular Rotation} = θ = (3/4 Turn) = (4.712 rad)
{Torque Applied to Disk} = τ

From Conservation of Rotational Kinetic Energy:
{Rotational Work} = τ*θ = {Final Rotational Kinetic Energy} - {Initial Rotational Kinetic Energy}
::: ⇒ τ*θ = (1/2)*I*(ωf)2 - (1/2)*I*(ω0)2
::: ⇒ τ*θ = (1/2)*I*{(ωf)2 - (ω0)2}
::: ⇒ τ*(4.712 rad) = (1/2)*(1.613 kg*m2)*{(0.0 rad/s)2 - (1.22 rad/s)2}
::: ⇒ τ*(4.712) = (-1.2)
::: ⇒ |τ| = (0.255 N*m)


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Thank you

Thank you for the help. It's greatly appreciated :smile:
 
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