Another problem (Phase Change Heat Calculation)

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Discussion Overview

The discussion revolves around a phase change heat calculation problem, specifically addressing the heat transfer involved in cooling a gas to a liquid and then further cooling the liquid. Participants explore the application of the heat transfer equations and the implications of temperature changes on the calculations.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • One participant presents a calculation for cooling a gas from 70 to 56 degrees and converting it to a liquid, using the equations q = mcat and mols * hvap.
  • Another participant questions the use of a negative value in the calculation for cooling the liquid, suggesting that cooling should not differ between states.
  • A participant explains that the negative value arises from the change in temperature calculation (final minus initial), specifically noting the cooling of the liquid from 56 to 0 degrees.
  • There is a discussion about the change in temperature for both the gas and the liquid, with one participant confirming the calculation for the liquid's temperature change.
  • Another participant suggests that heat should be added to the liquid cooling process, as it was used to cool the gas, indicating a potential misunderstanding of the heat transfer dynamics.

Areas of Agreement / Disagreement

Participants express differing views on the treatment of negative values in the calculations and the implications of temperature changes. The discussion remains unresolved regarding the correct approach to handling the heat transfer calculations.

Contextual Notes

Participants have not reached a consensus on the correct interpretation of the heat transfer equations in this context, and there are unresolved aspects regarding the assumptions made in the calculations.

Lori

Homework Statement



upload_2017-12-13_0-57-4.png

Homework Equations


q = mcat
mols*hvap

The Attempt at a Solution



To decrease temp from 70 to 56 degrees (bp), q=mcat = 1195.5
to convert this gas into liquid , must do mols * hvap = 29129 joules
to decrease temp from 56 to 0 thought, i get q= mcat = -7047 J (which is negative- is this wrong?)

it seems like the correct answer is when 7047 is positive after adding these up,. i get 37.37 kj. which seams like the answer (cant see it cause my professor erased it...)

Why wouldn't i subtract the last number?
 

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No idea where you got the minus from - cooling the liquid is no different from cooling the gas (for which you got the correct answer).
 
Borek said:
No idea where you got the minus from - cooling the liquid is no different from cooling the gas (for which you got the correct answer).
from mcat , i got the negative from change in temperature (final mius initial) so (0-56)
 
So, for colling of liquid ΔT = final - initial = 0 - 56 = -56, yes?

And what was the change in temperature for the cooling of gas?
 
Borek said:
So, for colling of liquid ΔT = final - initial = 0 - 56 = -56, yes?

And what was the change in temperature for the cooling of gas?
Oh I see. We are looking for any heat removed from cooling the gas so we should add heat to cool the liquid since it was used to cool the gas as well
 

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