Applications of Linear Systems: Electrical Networks

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To find the current through the central 1-ohm resistor in a Wheatstone bridge, it's essential to apply Kirchhoff's laws to establish the necessary equations. Redrawing the circuit can simplify the analysis by clarifying the current paths. Users are encouraged to label currents and use consistent notation to avoid confusion. While Kirchhoff's laws are a standard approach, alternative methods like star-triangle transformations can also be utilized. Ultimately, the choice of current direction is flexible, but it will affect the sign of the final results.
adc85
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Hey,

How do I find the current through the central resistor (the one that is 1 ohm) in this Wheatstone bridge attached to this post? What approach do I need to take here if I were to solve this using linear systems? Our professor poorly explained how electrical networks work. I can solve the linear system once I get it but I just need to figure out what I'm supposed to do in order to find those equations. Thanks.
 

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Try and redraw the circuit, but simplified so it's easier to see all the "routes" the current can go through. That really helps. :smile:
 
Another way, without using the Kirchoff's laws, would consist of using the star-triangle transformations and compute in this way the electric potentials at the ends of the central resistor using only the Ohm's laws.
 
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See that's the thing, he never drew any arrows in the problem. I think he said something like we can make up our own directions but I really couldn't understand him. Would the final answer be the same no matter what the directions were?
 
You can choose your own direction. If you have chosen your arrow in the 'wrong' direction, final answer will reflact that. In other words, you will get a negative result.
 
OK here's a revised drawing of the diagram. I labeled the direction of the current this time. Are these directions fine? I know next to nothing about how current, voltage, and resistance work.
 

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Now mark the currents with some notations, say I, i, i_1.

Say the current through the battory is I.

So at the 2 \Omega, 3\Omega junction (left side in your recent picture) , let the current through 3\Omega is i and current through 2\Omega is I-i (Point rule).

Do similarly at the 3,1,2 junction (top), assuming the current through 1\Omega is i_1. Complete the current flow diagram by writing the currents through the other resistors. Don't introduce any other variables.

You need only three variables namely I, i, i_1. Apply Kirchoff's laws to get three equations to solve.

Some one will be along with you if there is another easy way to do this.

regards,
 
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