Are two vectors that are orthogonal to a third parallel?

Vitani11
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Homework Statement


Is it true in three dimensions that any two vectors perpendicular to a third one are parallel to each other?

Homework Equations


Dot product.

The Attempt at a Solution


I've come up with two vectors that were orthogonal to a third and found the angle between them using the definition of the dot product and the angle was not 180 degrees. Therefore I don't think that it's true. I'm really only here to check that I did my math right. Is it actually not true, or do I need to recalculate?
 
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You're probably overthinking the problem. You should be able to easily come up with a counterexample which shows the statement is false.
 
Not in general, consider the dot products of two non-parallel vectors with the 0 vector.
 
If you want something visual, you might ponder the right hand rule...
 
Vitani11 said:
Dot product

In my opinion, you should try computing the cross product of two parallel vectors, since the cross product produces a vector normal to both those vectors. Can you do it? If you can answer that question, then you can answer the original question, I think. Given you know how to cross-multiply vectors. But since you're given only the definition of the dot product, you can kindly disregard this post.
 
Last edited:
Vitani11 said:
Is it true in three dimensions that any two vectors perpendicular to a third one are parallel to each other?
XYZ axes?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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