Asap help please~electric fields from continuous charge distribution?

AI Thread Summary
The discussion focuses on calculating the x-component of the electric field at a point above a uniformly charged nonconducting rod. The user presents their integral solution for the electric field and seeks validation of their answer. They express willingness to learn and improve their understanding of the topic. Additional resources were shared to aid in comprehension. The exchange highlights the collaborative nature of problem-solving in physics.
Major Mei
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Hello guys,

I tried to figure this out and I got my answer. I just want to check it. So would you guys please help me with it? Thank you!
Here is the question:
A nonconducting rod of length 2a has a charge Q uniformly distributed along it. Find the expression for x-component of the electric field at point P(a distance above one of the ends of the rod)

my answer:

Ex = Integral from x = -2a to 0 of [(k*Q/2a)*xdx/ (x^2+a^2)^(3/s2)]
set x^2+a^2 = y
x*dx = dy/2 also x = -2a y = 5a^2
x = 0 y =a^2

Ex = -2*(k*Q/4a)[1/sq rt(y)] within limits of y = 5a^2 to y = a^2]
= - (kQ/2a)*[1/sq rt(5a^2) – 1/sq rt(a^2)] = -(kQ/2a^2)[1/sq rt(5) -1]
= [kQ/(2a^2*sq rt(5))]*{sq rt(5) -1]

is that correct?
Thank you and I am willing to learn from you ;)
 
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