Aspect ratio of cylinder floating in water?

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SUMMARY

The aspect ratio (h/d) for a cylinder with a specific gravity of 0.65 floating vertically in water is determined using the formula H/d = 0.65/sqrt(8 x 0.65). This calculation is based on the principle that the center of mass (GM) equals the moment of inertia (I) divided by the volume (V) minus the buoyant force (BG). Understanding specific weights is crucial for applying this formula correctly, particularly in distinguishing between the specific weights of the cylinder and the fluid.

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jayjay112
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Aspect ratio of cylinder floating in water?

Hi,

Basically the question is:

What is the aspect ratio (h/d) for a cylinder of specific gravity 0.65 above which it will float vertically? (Note use GM = I/V - BG)
So i found a solution that is simliar and can help solve the problem. (please see attached)

Using this information would the ans be:

H/d = 0.65/sqrt(8 x 0.65)

I think the main problem is i don't fully understand the specific weights.

where it says h = specific weight /specific weight 2 x H

should specific weight /specific weight 2 be = 0.65

hope this makes sense thank you for your help
 

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Please let me know if I am being too vauge.
 

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