Average force of air resistance

AI Thread Summary
The discussion focuses on calculating the average force of air resistance experienced by a space shuttle glider during its descent. Initial calculations indicated a landing speed of 362.77 m/s without air resistance, derived from energy conservation principles. The user initially struggled with the air resistance calculation but identified that air resistance is a nonconservative force. After correcting their approach, they derived the average force of air resistance to be approximately 3608 N. The discussion highlights the importance of correctly applying energy equations and understanding the nature of forces in flight dynamics.
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[SOLVED] Average force of air resistance

In early test flights for the space shuttle using a "glider" (mass of 1500kg including pilot), it was noted that after a horizontal launch at 750km/h at a height of 4500m, the glider eventually landed at a speed of 300km/h. What would it's landing speed have been in the absence of air resistance? What was the average force of air resistance exerted on the shuttle if it came in at a constant angle of 10 degrees to the earth?

I converted vi to 208.33 m/s and vf to 83.33 m/s.

I think I answered the first part correctly using 1/2mvi^2 + mgyi = 1/2mvf^2 + mgyf. I calcualted vf = 362.77 m/s. I double checked this using kinematic equations and got the same answer.

I'm having problems with the second part. I believe air resistance is a nonconservative force. The only equation that I came up with is:

wnc = change in KE + change in PE

From this I derived:

Fyi cos 10 = 1/2mvf^2 - 1/2mvi^2 + mgyf - mgyi

Using this I came up with the answer -21097 N but this doesn't seem right. What am I missing here?
 
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I think I figured out where I went wrong.
d = yi/sin 10 making w = Fdcos 180 = -Fd = -F(yi/sin 10)

This would give me the following equation:

-F(yi/sin10) = (1/2mvf^2 - 1/2mvi^2) + (mgyf - mgyi)

Then solve for F. F = 3608N
 
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