Average shear stress in the glue joint between a spliced rod?

AI Thread Summary
To calculate the average shear stress in the glue joint of the spliced nylon rods, the tensile force of 500 lb must be divided by the area of the glue that bonds the sleeve to the rods. The glue only covers the inner surface of the sleeve and does not extend to the ends of the rods. Therefore, the correct area for shear stress calculation is based on the sleeve's inner diameter, not the full cross-section of the rods. This clarification is crucial for accurately determining the shear stress in the glue joint. Understanding the specific area of contact is essential for solving this problem correctly.
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Problem statement:
Two 3/4-in.-diameter nylon rods are spliced together by gluing a 2-in. section of plastic pipe over the rod ends, as shown in the figure. If a tensile force of P = 500 lb is applied to the spliced nylon rod, what is the average shear stress in the glue going between the pipe and rods?

Figure:
345zxbo.jpg


Obviously, {average shear stress} = {force} / {area}. But I am very confused when you take into account this splicing! Thank you in advance!
 
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Assume there is no glue between the ends of the nylon rods, i.e., all of the glue is between the surface of the rod ends and the sleeve.
 
SteamKing said:
Assume there is no glue between the ends of the nylon rods, i.e., all of the glue is between the surface of the rod ends and the sleeve.

How does that affect the problem? Is it as simple as {shear stress} = 500 lb / (pi/4 * (3/4)^2) ?
 
No, the glue doesn't cover the cross section ends of the rods, it covers the inner surface of the sleeve and bonds it to the 1" ends of the nylon rods.
 
SteamKing said:
No, the glue doesn't cover the cross section ends of the rods, it covers the inner surface of the sleeve and bonds it to the 1" ends of the nylon rods.

Ohh, so use the area that it covers to calculate the shear stress? And P for the force?

Thank you very much by the way!
 
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