Determine Wall Thickness for 1,000 in. Aluminum Tube to Support 10-kip Load

AI Thread Summary
To determine the required wall thickness for a 1,000 in. aluminum tube supporting a 10-kip load with a maximum axial stress of 30 ksi, it's essential to focus on normal stress rather than shearing stress. The correct formula involves calculating stress as load divided by the cross-sectional area. The initial approach using shearing stress was incorrect, as it misapplied the stress calculation. Users are advised to clarify their calculations and ensure they are using the appropriate stress formulas. Accurate calculations are crucial for ensuring the structural integrity of the tube under the specified load.
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An aluminum tube with an outside diameter of 1,000 in. will be used to support a 10-kip load. If the axial stress in the member must be limited to 30 ksi T or C, determine the wall thickness required for the tube. I used tau=shearing stress/area therefore 30(pie times 1-d)=10 but that is not correct Thanks
 
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https://www.physicsforums.com/showthread.php?t=94379
 
I believe the question refers to normal stress \sigma
 
Also remember that stress divided by area is not what you want. You want LOAD divided by area to get stress.
 

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