AZING! How does compressing a gas cause an increase in temperature?

AI Thread Summary
Compressing a gas in a cylinder with a piston increases its temperature due to the work done on the gas, which adds energy to it. This phenomenon occurs regardless of whether the gas behaves ideally or not, as the temperature rise is a fundamental result of energy input during compression. The process can be adiabatic, meaning no heat is exchanged with the environment, leading to a temperature increase as described by the first law of thermodynamics. The relationship between pressure, volume, and temperature is governed by the equation dQ = dU + PdV, where dQ is heat added, dU is internal energy change, and PdV represents work done. Ultimately, compressing a gas results in a temperature rise due to the energy dynamics involved in the process.
triber
Messages
1
Reaction score
0
If there is a cylinder filled with gas and a piston compresses the volume to 1/2 the size, the pressure increases to twice the original pressure. Why does the temperature go up? Is it because PV=nRT only works for ideal gasses, and the non-ideal gasses go up in temperature? Thanks.
 
Physics news on Phys.org
How does the volume go down?

(Does the piston drive forcefully into the gas, accelerating many individual molecules? Do you drive the piston infinitesimally slowly? Do you just wait until no molecules happen to be in part of the cylinder, and then close that part? Are you thinking of a big effect, occurring for all gases, or a small effect like deviation from the ideal gas law?)
 
Last edited:
Triber, was this a homework question? (It sounded to me like it should have been moved only to the classical+thermodynamics forum otherwise.. I wonder if there is a way to know who moved particular threads and why?)
 
triber said:
If there is a cylinder filled with gas and a piston compresses the volume to 1/2 the size, the pressure increases to twice the original pressure. Why does the temperature go up? Is it because PV=nRT only works for ideal gasses, and the non-ideal gasses go up in temperature? Thanks.
No. Temperature goes up for all gases. It is a matter of energy. When you compress a gas you do work on the gas. If it is adiabatic (with no heat flow into or out of the gas), the temperature has to increase because the work is an input of energy into the gas.

That is just the first law:

dQ = dU + PdV.

Since dQ = 0, dU = -PdV .

And since dU = nC_vdT, dT = -PdV/nC_v

AM
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top