nosepot said:
Beauty is in the eye of the beholder. I would not consider that explanation anything less than bamboozling. I'm trying to appeal to the idea of giving a plain explanation for a lay person. I don't dispute your spacetime diagram will convey that to a skilled individual, but to a layman it looks like trickery. Hidden in there somewhere, is the notion that the distance between origin and destination is apparently shorter for the traveller, which would probably satisfy most who protest that a paradox exists.
Didn't you read post #84 of this thread? I said in the first diagram
of the other thread depicting the rest frame of the blue stay-at-home twin (who remains at the spatial origin) that the black twin's destination is
9 light-months away. I even put the
9 in bold so you wouldn't miss it. It's at the coordinate time of 15 months. Do you see it? Maybe it would help to know that distances between two of the thick lines are established along the horizontal grid lines.
Then I said in both of the next two diagrams, the maximum distance the blue twin gets away from the black twin is
7.2 light-months. In the second diagram this happens at 12 months and in the third diagram it happens at 25.5 months. Do you see those two distances?
And then in the fourth diagram the blue twin only gets
4.5 light-months away from the black twin. Can you see it?
Hopefully, my extra explanation will help you understand where those distances are. If not, please try to help me understand why you think they are still hidden. I'd like to be able to communicate this to a lay person.
nosepot said:
The other thing I don't like about the Doppler version is that we must correct for the travel time of the light...
No you don't; at least you don't have to do anything special. As long as you use units like months and light-months, you just draw in the light signals along the 45-degree diagonals. It's especially easy on a computer--you just make sure there are no kinks in the lines. The only part that might be less than trivial is knowing where to place the dots for any observer that is moving but that is merely the Time Dilation factor (gamma) which I'm sure you already know about. You just place the dots higher up in Coordinate Time by the gamma factor. In this example, gamma is 1.25 at a speed of 0.6c so the first dot for the traveler is placed at the Coordinate Time of 1.25 months.
Or another way you can do it is to divide that Coordinate Time for each leg of travel by the gamma factor for that travel speed and then place the dots evenly spaced along the line. So for the first diagram, the traveling twin arrives at his destination at the Coordinate Time of 15 months so the Proper Time on his clock is 15/1.25=12 months. You can see that there are a total of 12 segments representing 12 months each along both of the black twin's travel legs.
If you had instead specified the time that the traveling twin took before he turned around according to the Proper Time on his clock, in this case 12 months, then you multiply that by the gamma factor to get the Coordinate Time. I presume you know what slope to draw the line for any particular speed.
nosepot said:
when solving from each inertial frame in turn to figure out how each appears to age (this is how most people would do it - sit themselves in the positions of each twin and start the experiment).
But to solve for each additional inertial frame, you just decide on a speed that you want it to move relative to the original one and then you plug the coordinates of each worldline's endpoints into the Lorentz Transformation formulas and plot them on a new graph and connect them with appropriate colored lines. Then you calculate gamma for each line segment based on its speed or you can simply just place the same number of dots equally spaced on each line segment. Finally, you draw in new light signals along the diagonals, just like you did before.
nosepot said:
The traveling twin is trying to observe that the Earth twin is aging slower,
But neither twin can actually observe the Time Dilation of the other twin. All they can do is observe the Doppler, which simply means they observe the progress of the other ones clock or they receive radio signals sent out at a predetermined and agreed on rate compared to their own. Then they can make some assumptions and construct a spacetime diagram after the scenario is all over but the specific diagram they make is dependent on the assumptions they make.
nosepot said:
but on the outward journey the wavefronts trickle in and during the return trip he is bombarded.
True, that's exactly what he will observe, no matter which frame you chose to depict it in. Have you noticed that? This is a description of what actually, in reality, for real happens. Why shouldn't this be pointed out in any analysis of the Twin Paradox?
nosepot said:
The same is true for the Earth twin.
Not true. The same does not happen for the Earth twin. The Earth twin does not see the change from trickle to bombarded until a long time after the half-way point of the time the traveler is gone. The faster the speed of the traveling, the more lopsided this change happens. And again, this is what actually happens.
nosepot said:
It's very confusing... but, each to their own.
I'm giving you insight into the brain of a Special Relativity retard. This should be gold! :)
But it would give me great pleasure to know that you have learned and can even teach this to someone else. That's the stated purpose of this forum. Don't give up. Ask questions until the confusion evaporates. Remember, Einstein said it was a simple theory and he was a genius so he should know.