Bernoulli equation in a closed loop system

AI Thread Summary
In a closed loop system, the discussion revolves around applying the Bernoulli equation to analyze pressure differences and head losses. The pressures at points P1 and P2 are given as 5 psi and 15 psi, respectively, with the assumption that the velocity of water remains constant due to a uniform pipe diameter. The key question is whether the head loss due to friction and the pump head can both equal 10 psi. Clarifications are made regarding the placement of points 1 and 2, indicating that P1 is after the expansion tank and P2 is after the pump. The conversation concludes with a confirmation of the two applicable Bernoulli equations for analyzing the system.
icham
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Homework Statement
Bernoulli equation in closed loop system
Relevant Equations
H=p/ρg+V2/2g+z2-p/ρg+V2/2g+z1=hs-hf
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P1 = 5psi P2= 15psi , Z2-Z1 = 0, i assume V2 =V1 because velocity of water is the same everywhere in a pipe of constant diameter
is H friction = H pump = 10psi ?
Please help
 

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Correct. Is that really your question?
 
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how come?
(p2- p1) +H friction = Hp
(15psi-5psi) +10psi = 10psi ?
 
icham said:
how come?
(p2- p1) +H friction = Hp
(15psi-5psi) +10psi = 10psi ?
The thing is in a loop, so if points 1 and 2 are right next to one another, say in the inlet pipe to the pump, P1 = P2
 
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Chestermiller said:
The thing is in a loop, so if points 1 and 2 are right next to one another, say in the inlet pipe to the pump, P1 = P2

but gauges show 15psi and 5psi and it should be a differential pressure for pump to work
 
icham said:
but gauges show 15psi and 5psi and it should be a differential pressure for pump to work
Please specify where you are placing points 1 and 2.
 
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Chestermiller said:
Please specify where you are placing points 1 and 2.

as showns on the circuit, P1 is just after the expansion tank and P2 is after pump let say 10 feet or like half way between pump and the resistance
 
icham said:
as showns on the circuit, P1 is just after the expansion tank and P2 is after pump let say 10 feet or like half way between pump and the resistance
OK. Then there are two Bernoulli equations that you can write: $$\frac{P_2-P_1}{\rho g}=\Delta H_{pump}$$That applies across the top; and $$\frac{P_2-P_1}{\rho g}=\Delta H_{friction}$$That applies across the bottom.
 
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Chestermiller said:
OK. Then there are two Bernoulli equations that you can write: $$\frac{P_2-P_1}{\rho g}=\Delta H_{pump}$$That applies across the top; and $$\frac{P_2-P_1}{\rho g}=\Delta H_{friction}$$That applies across the bottom.

Thank you very much ! you've made my day
 
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