Bonding in Solid State Physics

RedMech
Messages
13
Reaction score
0
1. The problem statement

The potential energy between two ions is
u(r) = -α/r2 + β/r8

Determine:

(i) The intermolecular distance ro for which the potential energy is minimum
(ii) The inter-atomic distance for which the potential energy is zero is

R= (2)-1/6ro

Homework Equations



du/dr=o at equilibrium distance, ro

The Attempt at a Solution



i) du/dr= 2α/r3 - 8β/r9 = 0 at equilibrium distance ro

we end up with

ro = (4β/α)1/6



ii) -α/r2 + β/r8 = 0

which give us

R-6 = α/β

We can express the ratio α/β interms of ro so that

R-6 = 4ro-6

and finally

R = (4)-1/6ro

My question now is why does my answer have a 4 instead of a 2 in it?
 
Last edited:
Physics news on Phys.org
Your result is correct, and it can be written also as R=2-1/3 r0.

ehild
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top