Calculate the temperature measured on the resistance scale

AI Thread Summary
To calculate the temperature measured on the resistance scale using the given formula R=R0 (1+ alphaT + betaT^2), one must substitute the constants alpha (3.8 x 10^-3 k^-1) and beta (-3.0 x 10^-6 k^-2) into the equation. The challenge lies in determining the resistance R at 70 degrees Celsius and solving for T. Clarification on the values of alpha and beta was provided, suggesting they are accurate for the calculation. The discussion emphasizes that all necessary information is present to arrive at the solution.
robgb
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Thermal physics question...

A wire resistance thermometer is constructed with material that has a resistance that varies as temperature as below.

R=R0 (1+ alphaT + betaT^2)
where constants alpha and beta are 3.8 x 10^-3 k^-1 and -3.0 x 10^-6 k^-2 respectively.

Calculate the temperature measured on the resistance scale at 70 degrees C on the ideal gas scale.

I've got no idea where to start on this one, any ideas?

Thanks, Rob.
 
Last edited:
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I've corrected the values of alpha and beta, does it make more sense now?

I've been told that this question has all the information you need to solve it.

Can anyone help?

Thanks, rob.
 

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