Calculate Work Done by Horse on Level Snowy Surface

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The discussion focuses on calculating the work done by a horse pulling a 120kg sleigh over a distance of 0.75km on a level snowy surface with a coefficient of kinetic friction of 0.25. The work done by the horse can be calculated using the formula W = F * S, where F is the force exerted by the horse and S is the distance. The net force on the sleigh is zero due to constant velocity, indicating that the force exerted by the horse equals the force of friction. The participant successfully solved the problem after considering the forces acting on the sleigh.

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1. A 120kg sleigh is pulled by one horse at a constant velocity for a distance of 0.75km on a level snowy surface. The coefficient of kinetic friction between the sleigh and the snow is 0.25. (a) calculate the work done by the horse. (b) calculate the work done by friction.



2. F= W * S



3. I really have no idea where to start. Thats all i really want to know. Any hints please?
 
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Shaunzio said:
1. A 120kg sleigh is pulled by one horse at a constant velocity for a distance of 0.75km on a level snowy surface. The coefficient of kinetic friction between the sleigh and the snow is 0.25. (a) calculate the work done by the horse. (b) calculate the work done by friction.
2. F= W * S
Try: Work = Force x distance where Force is the component of force in the direction of motion. Technically, it is: W = \vec{F}\cdot\vec{S}.

Since the sleigh is moving at constant velocity, what does that tell you about the net force on the sleigh?

What are the forces acting on the sleigh? What is the direction of the force exerted by the horse on the sleigh? What is the direction of the force that resists the pull of the horse? What determines the magnitude of this force (of resistance) which the horse is required to provide? Apply the above relation to determine the work.

AM
 
thanks i figured it out :)
 

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