Calculate Work Needed to Stop Rolling Cylinder

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SUMMARY

The work required to stop a homogeneous cylinder rolling without slipping is determined by calculating both its translational and rotational kinetic energy. For a cylinder with a radius of 30 cm and mass of 40 kg moving at 2.4 m/s, the translational kinetic energy (KE_linear) is 115 J, while the rotational kinetic energy (KE_rotation) is calculated using the moment of inertia (I) and angular velocity (ω). The total work needed to stop the cylinder is the sum of these two energies, resulting in a total of 172.6 J.

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A homogeneous cylinder of radius 30cm and mass 40kg is rolling without slipping along a horizontal floor at 2.4m/s. How much work is needed to stop the cylinder?

work = delta_KE in this case so oi figured .5 *40 * 2.4^2 = 115 J but this is not right, what should i do with the cylinder?
 
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i still can not figure this one out.
 
Besides KE of the center-of-mass moving in translation (linear),
you also have KE of the extended mass moving AROUND the c.o.m.

KE_rotation = 1/2 I (omega)^2
 
i did this and found omega to be 8 rad/s and I to be 1.8 then i found the KE to be 57.6 this is now right either.
 
"Besides" the old linear KE there's now rotational KE, ALSO.
The total KE is the SUM : KE_linear + KE_rotation
 

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