Calculating Angular Speed of an Alpha-Particle in a Magnetic Field

AI Thread Summary
An alpha-particle, consisting of two protons and two neutrons, has a mass of 6.64x10^-27 kg and is influenced by a 0.0195 T magnetic field. To calculate the angular speed (w) of the alpha-particle, the relationship w = qB/m is used, where q represents the charge of the alpha-particle. Since protons have a charge of 1.602x10^-19 C, the total charge (q) for the alpha-particle is 2 * 1.602x10^{-19} C. The discussion clarifies the necessary values and equations to find the angular speed, emphasizing the importance of understanding the charge of the particle. The calculation process is confirmed as correct, with the charge being the key variable needed to proceed.
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An alpha-particle is the nucleus of a helium atom; the orbiting electrons are missing. The alpha-particle contains two protons and two neutrons, and has a mass of 6.64x10^-27 kg. Suppose an alpha-particle is accelerated from rest through a potential difference and then enters a region where its velocity is perpendicular to a 0.0195 T magnetic field. With what angular speed w does the alpha-particle move on its circular path?

B = 0.0195 T
m = 6.64x10^-27 kg
w = ? rad/s

I did this:
v = rw
w = v/r
r = mv/qB
qB/m = v/r
w = qB/m

how ever I am stuck on what is q?
 
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your work looks right to me.

neutrons have 0 charge. protons have 1.602*10^{-19}C charge. so for your problem q is 2*1.602*10^{-19}C
 
thank you! :)
 

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